Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 15 of 21.
Suresh said:
1 decade ago
Excluding stoppages, the speed of a bus is 54 kmph.
Including stoppages, the speed of a bus is 45 kmph.
The difference between 54 and 45 is 9 that means the bus stopped.
Overall about 9 kms.
Formula : (Difference/Bigger value)*60.
Therefore (9/54)*60.
Including stoppages, the speed of a bus is 45 kmph.
The difference between 54 and 45 is 9 that means the bus stopped.
Overall about 9 kms.
Formula : (Difference/Bigger value)*60.
Therefore (9/54)*60.
Saurabh said:
1 decade ago
For those who got i2 min as answer.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
ARJUN SAHOO said:
1 decade ago
See..the bus runs up to 54 kmph in 60m. in nonstop mode.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
Arun said:
1 decade ago
Why you have taken 54 and why not 45?
Bala said:
1 decade ago
Due to the stoppages it travelled 9km less. So
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
Alok kumar mishra said:
1 decade ago
54km less if it stop for 1 hr.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
Ashish said:
1 decade ago
For all those who got answer as 12.
12 min is the stoppage time for (60+12) min i.e 72 min. So, for 60 min. i.e 1 hr it would be 60* 12/72=10 min.
12 min is the stoppage time for (60+12) min i.e 72 min. So, for 60 min. i.e 1 hr it would be 60* 12/72=10 min.
Sumit Dubey said:
1 decade ago
@Dushanthi,
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Dushanthi said:
1 decade ago
@Brijesh Kesharia,
40 + 45 + 50 + 55 + 60 + 65 + 70 = 385.
So, it takes 7 hrs.
40 + 45 + 50 + 55 + 60 + 65 + 70 = 385.
So, it takes 7 hrs.
Brijesh Kesharia said:
1 decade ago
A car starts running with the initial speed of 40 km/h with its speed increasing every hour by 5 km/h. How many hours will it take to cover a distance of 385 km?
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