Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = | ![]() |
9 | x 60 | ![]() |
= 10 min. |
54 |
Discussion:
205 comments Page 14 of 21.
Ronak Bhatia said:
10 years ago
For 60 min......54 kmph so.
For ? min.......45 kmph.
= 45*60/54 = 50 mins it means 10 mins less so it has stopped for 10 mins.
For ? min.......45 kmph.
= 45*60/54 = 50 mins it means 10 mins less so it has stopped for 10 mins.
Aditya said:
10 years ago
There is a formula for this questions:
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
Sha said:
1 decade ago
How can you take if t=1 randomly?
Sukumar Satyen said:
1 decade ago
Suppose bus will take t hours to cover certain distance, if there are stoppages, as we know speed = d/t = = 45kmph.
Total distance covered by bus = speed*time = 45t....equation(1).
If bus did not stop at those stoppages, where stoppage time was s hours, then bus actually saved s hours to cover same distance.
It means that due to travel time of (t-s) hours, the speed was increased, as we know speed = d/(t-s) = 54kmph.
Total distance covered by bus = speed*time = 54kmph*(t-s) = 54t - 54s...equation(2).
From equation (1) and (2),
54t-54s = 45t.
=> 54t-45t = 54s.
=> 9t = 54s.
=> 9t/54 = s.
=> s = t/6.
If t = 1 hour = 60 minutes,
Then, s = 60/6 = 10 minutes.
Total distance covered by bus = speed*time = 45t....equation(1).
If bus did not stop at those stoppages, where stoppage time was s hours, then bus actually saved s hours to cover same distance.
It means that due to travel time of (t-s) hours, the speed was increased, as we know speed = d/(t-s) = 54kmph.
Total distance covered by bus = speed*time = 54kmph*(t-s) = 54t - 54s...equation(2).
From equation (1) and (2),
54t-54s = 45t.
=> 54t-45t = 54s.
=> 9t = 54s.
=> 9t/54 = s.
=> s = t/6.
If t = 1 hour = 60 minutes,
Then, s = 60/6 = 10 minutes.
(1)
SANDEEP said:
1 decade ago
I will suggest one more formula to solve this kind of problems when stoppage time has to be calculated.
Then, stoppage time = 1-Slower speed/Faster speed.
Hence in this case.
= 1-45/54.
= 1- 5/6.
= (6-5)/6.
= 1/6.
Which can be converted to = 1/6*60 = 10 min.
Then, stoppage time = 1-Slower speed/Faster speed.
Hence in this case.
= 1-45/54.
= 1- 5/6.
= (6-5)/6.
= 1/6.
Which can be converted to = 1/6*60 = 10 min.
Guna said:
1 decade ago
Please explain in min to sec and min to hours.
Veeresh said:
1 decade ago
Why we are considering 54 kmph rather 45 kmph?
Surendra said:
1 decade ago
To all those who have doubt why 54 kmph is considered. The problem is to find how many minutes does the bus stops in stoppages.
54 kmph means it travels 54 km per a single hour (i.e 60 min) excluding stoppages.
Including stoppages speed reduced to 45 km per a single hour. It means per one hour due to stoppages there is 9 km loss per a single hour.
We should take 54 kmph because we should know what time it takes for bus for a km. So 54 km-->60 min then 1 km-->60/54 min.
For 9 km--> (9*60) /54 = 10 min.
54 kmph means it travels 54 km per a single hour (i.e 60 min) excluding stoppages.
Including stoppages speed reduced to 45 km per a single hour. It means per one hour due to stoppages there is 9 km loss per a single hour.
We should take 54 kmph because we should know what time it takes for bus for a km. So 54 km-->60 min then 1 km-->60/54 min.
For 9 km--> (9*60) /54 = 10 min.
Deba said:
1 decade ago
Why we are considering 54 kmph rather 45 kmph?
Lipu said:
1 decade ago
If speed is 54 kmph.
So in one hour bus travels 54 km.
Again time taken by bus to travel 54 km with speed 45 kmph will be (54/45) *60 min=72 min.
So to reach at the same position more time required 12 min.
So 12 min is the stopped time.
So in one hour bus travels 54 km.
Again time taken by bus to travel 54 km with speed 45 kmph will be (54/45) *60 min=72 min.
So to reach at the same position more time required 12 min.
So 12 min is the stopped time.
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