Aptitude - Time and Distance - Discussion

75/x * 1.5 = 75/x-12.5 (speed of car * 1.5 = speed pf train).
X= 37.5 time taken (min).
Car speed 75/(37.5/60) as time was in mins.

Let the speed of the car be x.

As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].

So, (150/100) x.

Please anyone can explain since the speed of the train is 1.5 * speed of the car, so how in the solution we are taking that difference of time is 12.5 min. How we come to know that if 12.5min added to the time taken by car will equal to the time taken by train?


Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.

@All.

So many of us are confused in where the hell this (150x/100) came from right.

So, my simple explanation is that see the train is 50% faster than car.

Now, consider car speed is X so the train speed will be (X+ 50% of X) Now calculate the train speed.

And you will get (X + 50X/100) = 150X/100.

Hope this helps.

Thanks for explaining the answer.

@All.

The soultion is;

Speed of car = x =>1x=>100/100x.
(All are literally same, in terms of percentage it's 100/100x).
Speed of train = 50%+ x=> (50/100)+(100/100x)=150/100x=3/2x.

I have an easier and simple solution.

The train is 50% faster than a car so for a 75km distance when the train reaches (without stopping) at B car will be some distance behind the train.

Well, train is 50% faster so the car should be at 50km when the train reaches point B (75km) (because 50 + 50% of 50 = 75).

And it's given that the train is 12.5 faster than a car (if it stops for 12.5 min and then after they reach at point B together).

Means rest of the distance (25km) car will cover in 12.5 min.

So, the speed of car = 50km/12. 5/60 hr = 120km/hr.

Thanks everyone for explaining the answer in a better way.

Let speed of car be x km/hr,
100% speed of car is x.
150% speed of train is x/100*150,
= 150x/100.

@Sahil Tiwari.

Thanks for explaining the answer in the simplest way.