Aptitude - Time and Distance - Discussion

Let the speed of the car = x.
So, the speed of the train will be 50% faster than the car i.e;
x + 50% of x = 1.5 x.

The Time taken by the car and train is same and the train lost 12.5 min or 12.5/60 hours on stops.
So,
Time taken by train = Time taken by car.
Time taken by train to cover 75km = (75/1.5x) - (12.5/60)Time lost.
Time taken by car to cover 75km = (75/x).
equate these equations and find x.

Let the speed of the train be x.
So, train speed 50% faster than car means x + x/2 = 3x/2, speed = 75km/hr, time delayed = 12.5 mins==12.5/60 sec. Now;
D/s = T; (here speed = speed of the car -speed of the train),
So,
75/x -75/3x/2 = 12.5/60.
75/x - 50/x = 5/24.
x = 25 x 24/5
x = 120 km/hr.

n any of the time distance sum out of time, distance, speed one of the quantities common
Here the time is common;

So we;
d = s*t.
Car Time = train Time.
Dist of car/Speed of car = Dist of train/Speed of train.
But here is train takes extra time for pause which must be equal.
Time train = Time of train running + Time train pass.
Time train running + Time train pass = Dist of car/Speed of the car.
Time train running - Dist car/Speed car = Time train pass.
75/1.5(x) -75/x = 12.5/60.
FYI (12.5/60 = 125/10*60),
x = 120Km/hr.

Someone help me in this by explaining this.

I did not understand. Please help me to get it.

Let the speed of car be x.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.

By ratio of Speed.

T :C = 150: 100,
= 3:2.
Since, Distance is constant.
Time ratio = 2:3.
Diff between time ratios 2 and 3 is 1, which means 1 = 12.5 mins.

1 -----> 12.5 min,
3------> 37.5min,
2 ------> 25 min,
,
Speed of Car = Distance/Time.
= (75 /37.5) * 60( For min to hr),
= 120km/hr.

75/x * 1.5 = 75/x-12.5 (speed of car * 1.5 = speed pf train).
X= 37.5 time taken (min).
Car speed 75/(37.5/60) as time was in mins.

Let the speed of the car be x.

As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].

So, (150/100) x.

Please anyone can explain since the speed of the train is 1.5 * speed of the car, so how in the solution we are taking that difference of time is 12.5 min. How we come to know that if 12.5min added to the time taken by car will equal to the time taken by train?


Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.