Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Discussion:
342 comments Page 34 of 35.
Aiswarya c v said:
5 years ago
Why was it taken 125/10 * 60?
Please explain.
Please explain.
Pintu said:
5 years ago
I think the answer is 110.
Shubham Boni said:
5 years ago
The Answer method, I correct with 1 simple mistake in calculations.
75/x - 75/(3x/2) = 12.5 minutes.
Now, the equation is correct but Now since time is in Minutes we need to convert it into seconds.
We Know, 1min = 60seconds this means, 12.5min = (12.5X 60)seconds.
75/x - 75/(3x/2) = 12.5 minutes.
Now, the equation is correct but Now since time is in Minutes we need to convert it into seconds.
We Know, 1min = 60seconds this means, 12.5min = (12.5X 60)seconds.
Rajuuu said:
4 years ago
Can anybody explain if both the vehicle reaches at the same time then where is the delay arises I am talking about if two vehicles reach at the same time then how this equation came?
(75/x) - (75/ (3/2) x) =12.5/60, 12.5 minutes delay will not be there if both the vehicles reach at the same time please help,
Let me explain, the time taken by car to reach B point is 40 min (just assume). Then the time taken by train is 27.5 min without stopping in stations. Hence 12.5 equal to the time taken by car (-) time taken by train without a stop in stations.
Hope you understand, thank you.
(75/x) - (75/ (3/2) x) =12.5/60, 12.5 minutes delay will not be there if both the vehicles reach at the same time please help,
Let me explain, the time taken by car to reach B point is 40 min (just assume). Then the time taken by train is 27.5 min without stopping in stations. Hence 12.5 equal to the time taken by car (-) time taken by train without a stop in stations.
Hope you understand, thank you.
Insane said:
4 years ago
If you guys wonder how did 12.5 converts in 125/60*10 then;
As 12.5 min should be converted into hours.
So, 12.5/60 (to remove decimal from 12.5 bcos we cant divide),
We add * 10,
125/ 60*10 or 125/600.
As 12.5 min should be converted into hours.
So, 12.5/60 (to remove decimal from 12.5 bcos we cant divide),
We add * 10,
125/ 60*10 or 125/600.
Arvind said:
4 years ago
T = D/S
T = 75/X-75/1.5X = 12.5/60.
T = 75/X-75/1.5X = 12.5/60.
Bishal Subba said:
4 years ago
@All.
It is just 12.5/60 in the RHS eliminate the 10.
You will get the answer as 120kmph.
It is just 12.5/60 in the RHS eliminate the 10.
You will get the answer as 120kmph.
Navin said:
4 years ago
@Sahil Tiwari.
Thanks for explaining the answer in the simplest way.
Thanks for explaining the answer in the simplest way.
Shruti said:
4 years ago
Let speed of car be x km/hr,
100% speed of car is x.
150% speed of train is x/100*150,
= 150x/100.
100% speed of car is x.
150% speed of train is x/100*150,
= 150x/100.
Golu said:
4 years ago
Thanks everyone for explaining the answer in a better way.
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