Aptitude - Time and Distance - Discussion

Car speed is X KMPH then,
Train speed=(car speed + (50*carspeed)/100),

ie train speed =(X+(50X/100)),

Take LCM and then(100X+50X)/100 . ie 150X/100,

Those who are not understanding 75/ 3/2.
For them (75*2) /3 = 50.

The car and train reached 75km at the same time.the train was late for 12.5 mins.
The train could reach 12.5 mins faster than the car.
* 75/x is the timing of car to reach 75kms.
*75/(3x/2) +12.5/60(time for stops) is the time taken by train to reach 75kms.
*Both the timings are equal since the time taken by both car and train are equal so then you can get the equation.
75/x = 75/(3x/2) + 12.5/60.
75/x - 75/(3x/2) = 12.5/60.

Why was it taken 125/10 * 60?

Please explain.

I think the answer is 110.

The Answer method, I correct with 1 simple mistake in calculations.
75/x - 75/(3x/2) = 12.5 minutes.
Now, the equation is correct but Now since time is in Minutes we need to convert it into seconds.
We Know, 1min = 60seconds this means, 12.5min = (12.5X 60)seconds.

Can anybody explain if both the vehicle reaches at the same time then where is the delay arises I am talking about if two vehicles reach at the same time then how this equation came?

(75/x) - (75/ (3/2) x) =12.5/60, 12.5 minutes delay will not be there if both the vehicles reach at the same time please help,

Let me explain, the time taken by car to reach B point is 40 min (just assume). Then the time taken by train is 27.5 min without stopping in stations. Hence 12.5 equal to the time taken by car (-) time taken by train without a stop in stations.

Hope you understand, thank you.

If you guys wonder how did 12.5 converts in 125/60*10 then;

As 12.5 min should be converted into hours.

So, 12.5/60 (to remove decimal from 12.5 bcos we cant divide),
We add * 10,
125/ 60*10 or 125/600.

T = D/S
T = 75/X-75/1.5X = 12.5/60.

@All.

It is just 12.5/60 in the RHS eliminate the 10.
You will get the answer as 120kmph.