Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 33 of 35.
Jay said:
5 years ago
How 3/2 come? Please explain.
Hani said:
5 years ago
@Shavra Yaqub Shah.
I'm not getting your answer method, please explain to me in detail.
I'm not getting your answer method, please explain to me in detail.
Navas said:
5 years ago
I'm not getting your answer method, please explain to me in detail.
Aldrin said:
5 years ago
Also, they assumed that the car didn't stop anywhere and was continuously travelling.
XiYoZ said:
5 years ago
How (24 *25)/5 came?
Vicky045 said:
5 years ago
By Change Minute to hours 12.5*60.
Am I right, then how 12.5/60? Please explain me.
Am I right, then how 12.5/60? Please explain me.
Anonymous said:
5 years ago
@VIcky045.
Actually,
To take delay time of train we need to have express time in hr(given is in min).
To convert Minute to Hour (x minutes/60).
To convert Hour to Minute (x hours*60).
So,
Converting 12.5 mins to 12.5/60 hour.
125/10*60 also correct since it only removes decimals.
Actually,
To take delay time of train we need to have express time in hr(given is in min).
To convert Minute to Hour (x minutes/60).
To convert Hour to Minute (x hours*60).
So,
Converting 12.5 mins to 12.5/60 hour.
125/10*60 also correct since it only removes decimals.
Gabbar said:
5 years ago
Car speed is X KMPH then,
Train speed=(car speed + (50*carspeed)/100),
ie train speed =(X+(50X/100)),
Take LCM and then(100X+50X)/100 . ie 150X/100,
Train speed=(car speed + (50*carspeed)/100),
ie train speed =(X+(50X/100)),
Take LCM and then(100X+50X)/100 . ie 150X/100,
Aditya said:
5 years ago
Those who are not understanding 75/ 3/2.
For them (75*2) /3 = 50.
For them (75*2) /3 = 50.
Rakkesh said:
5 years ago
The car and train reached 75km at the same time.the train was late for 12.5 mins.
The train could reach 12.5 mins faster than the car.
* 75/x is the timing of car to reach 75kms.
*75/(3x/2) +12.5/60(time for stops) is the time taken by train to reach 75kms.
*Both the timings are equal since the time taken by both car and train are equal so then you can get the equation.
75/x = 75/(3x/2) + 12.5/60.
75/x - 75/(3x/2) = 12.5/60.
The train could reach 12.5 mins faster than the car.
* 75/x is the timing of car to reach 75kms.
*75/(3x/2) +12.5/60(time for stops) is the time taken by train to reach 75kms.
*Both the timings are equal since the time taken by both car and train are equal so then you can get the equation.
75/x = 75/(3x/2) + 12.5/60.
75/x - 75/(3x/2) = 12.5/60.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers