Aptitude - Time and Distance - Discussion

The Answer method, I correct with 1 simple mistake in calculations.
75/x - 75/(3x/2) = 12.5 minutes.
Now, the equation is correct but Now since time is in Minutes we need to convert it into seconds.
We Know, 1min = 60seconds this means, 12.5min = (12.5X 60)seconds.

Can anybody explain if both the vehicle reaches at the same time then where is the delay arises I am talking about if two vehicles reach at the same time then how this equation came?

(75/x) - (75/ (3/2) x) =12.5/60, 12.5 minutes delay will not be there if both the vehicles reach at the same time please help,

Let me explain, the time taken by car to reach B point is 40 min (just assume). Then the time taken by train is 27.5 min without stopping in stations. Hence 12.5 equal to the time taken by car (-) time taken by train without a stop in stations.

Hope you understand, thank you.

If you guys wonder how did 12.5 converts in 125/60*10 then;

As 12.5 min should be converted into hours.

So, 12.5/60 (to remove decimal from 12.5 bcos we cant divide),
We add * 10,
125/ 60*10 or 125/600.

T = D/S
T = 75/X-75/1.5X = 12.5/60.

@All.

It is just 12.5/60 in the RHS eliminate the 10.
You will get the answer as 120kmph.

@Sahil Tiwari.

Thanks for explaining the answer in the simplest way.

Let speed of car be x km/hr,
100% speed of car is x.
150% speed of train is x/100*150,
= 150x/100.

Thanks everyone for explaining the answer in a better way.

Thanks for explaining the answer.

Please anyone can explain since the speed of the train is 1.5 * speed of the car, so how in the solution we are taking that difference of time is 12.5 min. How we come to know that if 12.5min added to the time taken by car will equal to the time taken by train?


Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.