Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 30 of 35.
Varsha said:
6 years ago
How can we assume that car speed is 100 not other than that speed?
Bittu said:
6 years ago
Let car speed is x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
Helip said:
6 years ago
If we have to convert the minute in the second we will multiply with 60 then what does it mean in solution 125/10*60? Please tell me.
VIJAY said:
6 years ago
Here, we can use Car travel time = train travel time + stoppage time.
Shashidhar said:
6 years ago
Given.
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Aishwarya said:
6 years ago
Let the Speed of car be=x km/hr.
Speed of train = 1.5x km/hr.
Time taken by car to travel 75km = 75/x h.
Time taken by train to travel 75 km = 75/1.5 x-12.5/60.
Both are equal.
75/x = 75/1.5x-12.5/60.
1/x(75"75/1.5) = 12.5/60.
25/x = 12.5/60
1500 = 12.5x.
So, x = 1500/12.5 = 120 km/hr is the Answer.
Speed of train = 1.5x km/hr.
Time taken by car to travel 75km = 75/x h.
Time taken by train to travel 75 km = 75/1.5 x-12.5/60.
Both are equal.
75/x = 75/1.5x-12.5/60.
1/x(75"75/1.5) = 12.5/60.
25/x = 12.5/60
1500 = 12.5x.
So, x = 1500/12.5 = 120 km/hr is the Answer.
Sharada said:
6 years ago
How can you get that 150/100? please explain that.
Anomie said:
6 years ago
Let the car speed be x.
50% of car speed =50/100*x = x/2.
The train speed = x+x/2 = 3x/2.
50% of car speed =50/100*x = x/2.
The train speed = x+x/2 = 3x/2.
Anandhu said:
6 years ago
Can anybody tell me that, In the question, it states that the car and the train start at the same time from A and reach at the same time a B. Which means they took the same time to reach point B from A, so how can we take the difference of time taken by them?
Sandhya said:
6 years ago
Can you explain 125/10*60 how it got or is there any simple method for answering this question.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers