Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 29 of 35.
Ivdurp said:
7 years ago
We always consider percentage to 100 right.
They have given that train speed 50 % more than a car. here they take car speed as x.
We already we knew the percentage is (100+50)*x/100.
They have given that train speed 50 % more than a car. here they take car speed as x.
We already we knew the percentage is (100+50)*x/100.
Ameer said:
7 years ago
The speed of the car - speed of the train = loss time.
Abraham said:
7 years ago
Speed of car be x.
Speed of train= x+x/2 = 3x/2 ie; 1.5x.
Train didnt run for 12.5min ie; 12.5/60 hrs.
Difference between time ran by both is 12.5/60hr.
ie: (75/x) - (75/1.5x) = 12.5/60.
Upon solving x= 120kmph.
Speed of train= x+x/2 = 3x/2 ie; 1.5x.
Train didnt run for 12.5min ie; 12.5/60 hrs.
Difference between time ran by both is 12.5/60hr.
ie: (75/x) - (75/1.5x) = 12.5/60.
Upon solving x= 120kmph.
Neranjan said:
6 years ago
A to B have 75km.
We think, Train not stopped,
It can go 112.5km.
So, train speed =112.5km-75km/12.5m.
12.5m covert to hour 12.5/60.
= 37.5km * 60/12.5,
= 180kmph.
So car speed =180kmph * 100/150.
=120kmph.
We think, Train not stopped,
It can go 112.5km.
So, train speed =112.5km-75km/12.5m.
12.5m covert to hour 12.5/60.
= 37.5km * 60/12.5,
= 180kmph.
So car speed =180kmph * 100/150.
=120kmph.
Sandip said:
6 years ago
Speed of train:speed of car = 3/2:1 = 3:2.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Varsha said:
6 years ago
How can we assume that car speed is 100 not other than that speed?
Bittu said:
6 years ago
Let car speed is x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
Helip said:
6 years ago
If we have to convert the minute in the second we will multiply with 60 then what does it mean in solution 125/10*60? Please tell me.
VIJAY said:
6 years ago
Here, we can use Car travel time = train travel time + stoppage time.
Shashidhar said:
6 years ago
Given.
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
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