Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
353 comments Page 36 of 36.
Shivam said:
4 years ago
Thanks for explaining the answer.
Ayush said:
4 years ago
Please anyone can explain since the speed of the train is 1.5 * speed of the car, so how in the solution we are taking that difference of time is 12.5 min. How we come to know that if 12.5min added to the time taken by car will equal to the time taken by train?
Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.
Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.
Devaraj R A said:
6 days ago
For every 10km he walked, he walked an extra 4km.
So the question is, if he walked an extra 20 km, what would be the actual distance he covers?
Then 10 × 20/4 = 50.
So the question is, if he walked an extra 20 km, what would be the actual distance he covers?
Then 10 × 20/4 = 50.
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