Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
345 comments Page 20 of 35.

Arun sanap said:   1 decade ago
Hey. I can't get how they take 125/10*60. In that I understand 125/60 but. How they take 10? Please help me.

Rajesh.r.kzm said:   9 years ago
12.5 can be taken as 125/10. So it will be multiplied by no of minutes in an hour. So, it is 125/(10*60).

Prasad chowdary said:   1 decade ago
Hi, @Arun to remove the decimal form 12.5. We multiply and divide 10.

(12.5*10)/10 = 125/10.

Palani said:   9 years ago
But in question (50% more) is not given, only 50% faster is given so explain me the correct solution.

Sameer azmi said:   7 years ago
The train speed of the train is 50% more the speed of the car = x + 50%x/100.

Then, (100x+50x) /100.

Ranjeet said:   1 decade ago
Let suppose car speed = x km/h

As per problem train speed 50% more than car so = x+50/100x = 3/2x.

Meetali said:   1 decade ago
If speed is x, how do you'll apply the formula in 75/x i.e distance upon speed gives time isn't it?

Praveenkumar said:   9 years ago
Hi guys,

Can anyone explain why we are subtracting car speed 75/x from train speed i.e. 75/(3/2)x?

Radha said:   7 years ago
Can anybody tell me why we need to subtract 75/x with 75÷3/2x instead we can add it also right?

Shruti said:   4 years ago
Let speed of car be x km/hr,
100% speed of car is x.
150% speed of train is x/100*150,
= 150x/100.


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