Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 20 of 35.
Srivishnu said:
8 years ago
It's 12.5 minutes.
To convert it to an hour it should be divided by 60.
i.e 12.5/60 hrs (or)125/(60*10) hrs.
To convert it to an hour it should be divided by 60.
i.e 12.5/60 hrs (or)125/(60*10) hrs.
Shashidhar said:
6 years ago
Given.
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Sravani said:
5 years ago
Why to subtract the speed of the train from speed of car (75/x-75x/[3/2])?
Can anyone help me by explaining?
Can anyone help me by explaining?
(1)
Arun sanap said:
1 decade ago
Hey. I can't get how they take 125/10*60. In that I understand 125/60 but. How they take 10? Please help me.
Rajesh.r.kzm said:
9 years ago
12.5 can be taken as 125/10. So it will be multiplied by no of minutes in an hour. So, it is 125/(10*60).
Prasad chowdary said:
1 decade ago
Hi, @Arun to remove the decimal form 12.5. We multiply and divide 10.
(12.5*10)/10 = 125/10.
(12.5*10)/10 = 125/10.
Palani said:
9 years ago
But in question (50% more) is not given, only 50% faster is given so explain me the correct solution.
Sameer azmi said:
7 years ago
The train speed of the train is 50% more the speed of the car = x + 50%x/100.
Then, (100x+50x) /100.
Then, (100x+50x) /100.
Ranjeet said:
1 decade ago
Let suppose car speed = x km/h
As per problem train speed 50% more than car so = x+50/100x = 3/2x.
As per problem train speed 50% more than car so = x+50/100x = 3/2x.
Meetali said:
1 decade ago
If speed is x, how do you'll apply the formula in 75/x i.e distance upon speed gives time isn't it?
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