Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 19 of 35.
Fazil said:
1 decade ago
Can't we say speed of train is 50% faster than car.
If speed of car is x, then train must move with 2x speed. Is it?
If speed of car is x, then train must move with 2x speed. Is it?
Saloni Adhikari said:
2 years ago
Here, How can we say given time in the question is equal to the value obtained after subtraction? Please explain me.
(13)
Karthik said:
1 decade ago
It says 50% more than Car's speed.
So if car's speed is X the train's speed is = (X+(50/100)X).
Hence (150/100)X.
So if car's speed is X the train's speed is = (X+(50/100)X).
Hence (150/100)X.
Sagar Bhamare said:
9 years ago
The total speed of a car 100% + 50% extra,
So the speed of the train is 150%.
Which can be written as (150/100)X.
So the speed of the train is 150%.
Which can be written as (150/100)X.
Tabish said:
1 decade ago
Actually it is 50% more.
i.e (100% + 50 %) * x.
((100/100) + (50/100)) * x.
(1 + (50/100)) * x.
(150/100) * x.
i.e (100% + 50 %) * x.
((100/100) + (50/100)) * x.
(1 + (50/100)) * x.
(150/100) * x.
Bhumi said:
10 years ago
Car speed = x.
Train speed is 50% more.
Train speed = x+ (50/100) x = 100x + 50x/100.
= 150x/100.
= 3/2x Kmph.
Train speed is 50% more.
Train speed = x+ (50/100) x = 100x + 50x/100.
= 150x/100.
= 3/2x Kmph.
Rias said:
9 years ago
75km/s * 60 second = 4500sec,
50%-12.5 the train lost =37.5,
Speed = Distance/time.
then 4500sec/37.5 = 120km.
50%-12.5 the train lost =37.5,
Speed = Distance/time.
then 4500sec/37.5 = 120km.
(1)
Yash said:
6 years ago
Let Car speed is x.
The train speed is 50% faster than x.
Then the train speed is x+50%of x.
x+50x/100 =150x/100.
The train speed is 50% faster than x.
Then the train speed is x+50%of x.
x+50x/100 =150x/100.
Suja said:
1 decade ago
@ jamal:
We know that time=(distance/speed).
Here distance=75kmph and speed=3x/2.
Therefore time=75/(3x/2)
We know that time=(distance/speed).
Here distance=75kmph and speed=3x/2.
Therefore time=75/(3x/2)
NITISH GULERIA said:
1 decade ago
Hello friends don't confuse 50% more means x+50% = x+50/100, = x+1/2.
= LCM are 2 and whole equation are 3x/2.
= LCM are 2 and whole equation are 3x/2.
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