Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
345 comments Page 21 of 35.

Animesh Biswas said:   2 years ago
T:C ( speed) = 3:2.
T:C ( time) = 2:3.
Time is taken by car = 12.5× 3.
Speed of the car = 120 km/h.
(53)

Eleanor said:   10 years ago
@Abhishek Banik.

Can you please explain from the T of car - T of train?

You have lost me there.

Anonymous said:   1 decade ago
Let the speed of the car be x.

Then 50 percent of x = x/2.

Speed of the train = x + x/2 = 3x/2.

Amit Chauhan LPU said:   9 years ago
150/100 X it came because.

50% more than X ie :

=> (50/100) * x + x.
==> 150/100 * x.

Nng said:   8 years ago
Hi, can you please explain why we are subtracting the time of car and train to get 12.5 minutes?

Navik said:   2 years ago
T:C ( speed) = 3:2.
T:C ( time) = 2:3.
Time taken by car = 12.5× 3.
Speed of the car = 120 km/h.
(110)

Bhupat said:   1 decade ago
All righ but my question is. No body has taken 12.5 minus loss in train speed calculation. Why?

Sandhya said:   6 years ago
Can you explain 125/10*60 how it got or is there any simple method for answering this question.

Manu said:   1 decade ago
50% more than the car speed means lets car speed is 100 usual assumption 50% more means 150%.

Gayuverma said:   9 years ago
Can this question be solved using relative speed concept? If no, why? If yes, please show it.


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