Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 15 of 35.
Nitesh Nandwana said:
2 decades ago
Hi guys think simple not complicated.
Let speed of the Car be x kmph. so, 50% of x = x/2
Train speed = Car speed + 50% of Car speed
Train speed = x + x/2 = 3/2x
Let speed of the Car be x kmph. so, 50% of x = x/2
Train speed = Car speed + 50% of Car speed
Train speed = x + x/2 = 3/2x
Rakesh said:
10 years ago
If you take speed of train 50/ more than car, let us assume car speed 100 the train speed is 150. Hello Shobha, minutes convert in seconds multiply with 60 SND.
Sreenadh reddy said:
6 years ago
The train speed is 50% faster than the car. If the car is moving in 100 then the train moves 50% fast i.e. (100car speed+ 50faster speed) so they taken 150/100.
Jothi said:
1 decade ago
What you mean by percentage ? hey its not the additional value to add with existent one number. How its possible to 3/2 for 50% ? 1/2 is only possible for 50%.
Santhiraju said:
2 decades ago
Car speed is X KMPH then
Train speed=(car speed + (50*carspeed)/100)
ie train speed =(X+(50X/100))
Take LCM and then(100X+50X)/100 .....ie 150X/100
Train speed=(car speed + (50*carspeed)/100)
ie train speed =(X+(50X/100))
Take LCM and then(100X+50X)/100 .....ie 150X/100
Shro said:
1 decade ago
I am not understanding the main calculation part i.e. steps after finding speed pf the train.
Somebody please explain me the steps of main calculation
Somebody please explain me the steps of main calculation
Gabbar said:
5 years ago
Car speed is X KMPH then,
Train speed=(car speed + (50*carspeed)/100),
ie train speed =(X+(50X/100)),
Take LCM and then(100X+50X)/100 . ie 150X/100,
Train speed=(car speed + (50*carspeed)/100),
ie train speed =(X+(50X/100)),
Take LCM and then(100X+50X)/100 . ie 150X/100,
Saravan said:
2 decades ago
75/x - 75/(3/2)x = 125 /10*60
plz explain me why we subtract the train speed from car speed i didnt understood this step. can anyone explain me.
plz explain me why we subtract the train speed from car speed i didnt understood this step. can anyone explain me.
Bhushan said:
3 years ago
Let the speed of car be x.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
(16)
Bittu said:
6 years ago
Let car speed is x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
Train speed is 50% faster than car it means,
Car speed(x) +50%of car speed=x+50%x,
50% means 0.5, i.e, x+0.5x = 1.5x or 3/2x.
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