Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
355 comments Page 15 of 36.
Anandhi said:
6 years ago
@Anjali.
12.5 minutes lost in stopping so(time difference).
12.5/60 (dividing by 60 for converting minutes to hours).
To remove decimal dividing by 10.
125/10 * 60.
12.5 minutes lost in stopping so(time difference).
12.5/60 (dividing by 60 for converting minutes to hours).
To remove decimal dividing by 10.
125/10 * 60.
Sharad bhosale said:
1 decade ago
Suppose car speed is 'x' km/hr and speed of train is 50% higher than car speed,
i.e. [ x + 50/100x].
Hence [ x + 0.5x] = 1.5x.
i.e. 150/100x this is speed of car.
i.e. [ x + 50/100x].
Hence [ x + 0.5x] = 1.5x.
i.e. 150/100x this is speed of car.
Sandip said:
7 years ago
Speed of train:speed of car = 3/2:1 = 3:2.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Devaraj R A said:
4 months ago
For every 10km he walked, he walked an extra 4km.
So the question is, if he walked an extra 20 km, what would be the actual distance he covers?
Then 10 × 20/4 = 50.
So the question is, if he walked an extra 20 km, what would be the actual distance he covers?
Then 10 × 20/4 = 50.
(6)
Dr John said:
8 years ago
@All. The time lost by the train (12.5min) was already given in the question. We can't calculate the lost time without knowing other quantities( speed of car, etc).
Nitesh Nandwana said:
2 decades ago
Hi guys think simple not complicated.
Let speed of the Car be x kmph. so, 50% of x = x/2
Train speed = Car speed + 50% of Car speed
Train speed = x + x/2 = 3/2x
Let speed of the Car be x kmph. so, 50% of x = x/2
Train speed = Car speed + 50% of Car speed
Train speed = x + x/2 = 3/2x
Rakesh said:
1 decade ago
If you take speed of train 50/ more than car, let us assume car speed 100 the train speed is 150. Hello Shobha, minutes convert in seconds multiply with 60 SND.
Sreenadh reddy said:
7 years ago
The train speed is 50% faster than the car. If the car is moving in 100 then the train moves 50% fast i.e. (100car speed+ 50faster speed) so they taken 150/100.
Jothi said:
1 decade ago
What you mean by percentage ? hey its not the additional value to add with existent one number. How its possible to 3/2 for 50% ? 1/2 is only possible for 50%.
Santhiraju said:
2 decades ago
Car speed is X KMPH then
Train speed=(car speed + (50*carspeed)/100)
ie train speed =(X+(50X/100))
Take LCM and then(100X+50X)/100 .....ie 150X/100
Train speed=(car speed + (50*carspeed)/100)
ie train speed =(X+(50X/100))
Take LCM and then(100X+50X)/100 .....ie 150X/100
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