Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 14 of 35.
Nithishkumar said:
12 months ago
150/100 came because;
Car speed is 100% and train speed is 50% faster than a car so,
Car speed (100/100)+(50/100),
=(1/1)+(50/100),
Cross multiply then (100+50)/100.
= 150/100.
Car speed is 100% and train speed is 50% faster than a car so,
Car speed (100/100)+(50/100),
=(1/1)+(50/100),
Cross multiply then (100+50)/100.
= 150/100.
(56)
Jithen M S said:
3 months ago
(The train can travel 50% faster than a car).
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
(6)
Neo said:
1 decade ago
Here 150/100 how it come means.
Actually they said train 50%more than speed of car.
So train actually speed was 100% means 100/100 and he said 50 more so 150/100 that's it.
Actually they said train 50%more than speed of car.
So train actually speed was 100% means 100/100 and he said 50 more so 150/100 that's it.
Santhosh said:
1 decade ago
Here,in this problem if we take 50/100 then it becomes 1/2
So we have to take 50% more..
So,assuming car speed is 100 %,then increase it to 50%..means 100+50/100 = 150/100
So we have to take 50% more..
So,assuming car speed is 100 %,then increase it to 50%..means 100+50/100 = 150/100
AP bhai said:
2 years ago
Case1: For car;
D = TV.
75=TV.
Case2:
75={T+(12.5/60)}*1.5V.
75={(60T+12.5)*V}/40.
Now, compare case 1&2.
You get, T = 12.5/20;
As. D = TV.
75 = 12.5/20*V,
V = 120.
D = TV.
75=TV.
Case2:
75={T+(12.5/60)}*1.5V.
75={(60T+12.5)*V}/40.
Now, compare case 1&2.
You get, T = 12.5/20;
As. D = TV.
75 = 12.5/20*V,
V = 120.
(4)
Rahul said:
9 years ago
Let Car speed = x kmph.
Train's speed is 50% more than car.
So, train's speed = x + 50x/100.
= 150x / 100.
= 3x/2.
Train's speed is 50% more than car.
So, train's speed = x + 50x/100.
= 150x / 100.
= 3x/2.
Anandhi said:
5 years ago
@Anjali.
12.5 minutes lost in stopping so(time difference).
12.5/60 (dividing by 60 for converting minutes to hours).
To remove decimal dividing by 10.
125/10 * 60.
12.5 minutes lost in stopping so(time difference).
12.5/60 (dividing by 60 for converting minutes to hours).
To remove decimal dividing by 10.
125/10 * 60.
Sharad bhosale said:
1 decade ago
Suppose car speed is 'x' km/hr and speed of train is 50% higher than car speed,
i.e. [ x + 50/100x].
Hence [ x + 0.5x] = 1.5x.
i.e. 150/100x this is speed of car.
i.e. [ x + 50/100x].
Hence [ x + 0.5x] = 1.5x.
i.e. 150/100x this is speed of car.
Sandip said:
6 years ago
Speed of train:speed of car = 3/2:1 = 3:2.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Then time should be in 2:3,
The difference is 12.5min.
That means 1 part=12.5.
3pt=37.5min=37.5/60,
Speed=75/37.5/60= 120.
Dr John said:
7 years ago
@All. The time lost by the train (12.5min) was already given in the question. We can't calculate the lost time without knowing other quantities( speed of car, etc).
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