Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
355 comments Page 13 of 36.
Yogeshwar yaduwanshi said:
1 decade ago
Suppose car speed : x.
Than 50% more speed train : 3x/2.
Than formula car is taken time : 75/x = T....(1).
And train is taken time : 75*2/3x = T-12.5/60....(2).
Both equation solve: x = 120 km/hr.
Than 50% more speed train : 3x/2.
Than formula car is taken time : 75/x = T....(1).
And train is taken time : 75*2/3x = T-12.5/60....(2).
Both equation solve: x = 120 km/hr.
Amit said:
1 decade ago
Sarvya Kanchna is right:-)
dont consider x with 100 consider with 50 like this.
=x+50x/100
=(100x+50x)/100
=150x/100
If you consider x with 100 then when we take LCM then eq.
=(100x^2+50)/100x
:-)
dont consider x with 100 consider with 50 like this.
=x+50x/100
=(100x+50x)/100
=150x/100
If you consider x with 100 then when we take LCM then eq.
=(100x^2+50)/100x
:-)
Preethi said:
1 decade ago
75/x - 75/(3/2)x is in KMPH and the term 12.5 mins is converted into secs. how could the answer can be given in KMPH by equating these two terms? please anyone who knows the explanation, explain me?
Vibha said:
1 decade ago
Since the Car covered the half distance while train was halting, the speed of car becomes 75/2 * 60/12.5 = 180KM/hr
Now Train is 50% faster than car so train's speed should be 180 + 90 = 270 KM/hr
Now Train is 50% faster than car so train's speed should be 180 + 90 = 270 KM/hr
Tarun said:
1 decade ago
Lost time is equal to difference between the time taken by car in X kmph and time taken by train in 150/100X kmph distance is same for both 75 kms.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
Viji said:
8 years ago
The speed of the train is 50% more than a car.
If the car travels at x kmph then 50%of x is x/2kmph.
Note train travels 50% more which means actual x and 50% of x is x/2 together (x+x/2) =3x/2.
If the car travels at x kmph then 50%of x is x/2kmph.
Note train travels 50% more which means actual x and 50% of x is x/2 together (x+x/2) =3x/2.
Vidhyasaagar said:
5 years ago
@All.
The soultion is;
Speed of car = x =>1x=>100/100x.
(All are literally same, in terms of percentage it's 100/100x).
Speed of train = 50%+ x=> (50/100)+(100/100x)=150/100x=3/2x.
The soultion is;
Speed of car = x =>1x=>100/100x.
(All are literally same, in terms of percentage it's 100/100x).
Speed of train = 50%+ x=> (50/100)+(100/100x)=150/100x=3/2x.
(1)
Frustrated engineer said:
9 years ago
A train can travel 50% faster than a car.
That means IF CAR SPEED IS X, THEN TRAIN SPEED SHOULD BE 2X. Double speed of car. So how can you guys say 50% more speed?
How this 150x/100 comes?
That means IF CAR SPEED IS X, THEN TRAIN SPEED SHOULD BE 2X. Double speed of car. So how can you guys say 50% more speed?
How this 150x/100 comes?
Bhavi said:
8 years ago
Speed of train =( 1 + 50% )of speed of car.
75/t-12.5 = (1+1/2)75/t,
t=37.5 minutes,
Car speed = (2/3) * train speed,
Car speed = (2/3)*75/(37.5-12.5),
Car speed = 2 kmpm,
2 * 60 = 120 kmph.
75/t-12.5 = (1+1/2)75/t,
t=37.5 minutes,
Car speed = (2/3) * train speed,
Car speed = (2/3)*75/(37.5-12.5),
Car speed = 2 kmpm,
2 * 60 = 120 kmph.
Aliya said:
1 decade ago
Its not in same time it is at same time if we consider car starts at 10 to reach at 12 then train also have at same time but it is only possible with different speed if have time lag.
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