Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 16 of 35.
Tharun kumar said:
4 years ago
Let the speed of the car be x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
(1)
Ravi kataria said:
9 years ago
As a train is much faster, then time difference must be [distance /train speed - distance /car speed =12.5min].
Then, how it does inversely?
Then, how it does inversely?
Rajan said:
1 decade ago
Say, the speed of the car be 1 km/hr (0. 5 +0. 5).
And if there is 50% increase in speed means (1 +0. 5) = 1. 5 km /hr.
That's how 3/2 came.
And if there is 50% increase in speed means (1 +0. 5) = 1. 5 km /hr.
That's how 3/2 came.
Mohit said:
2 decades ago
Hey look it say train travels 50% faster then car. Suppose car travels at x speed than train travels at 50x. So its 150/100 thats as a % age.
RAMJAN RAEEN said:
7 years ago
Can anyone explain to me how 75/X - 75/ (3x/2) = 12.5?
How the time is the same in both case car and train if a halt is not considering?
How the time is the same in both case car and train if a halt is not considering?
Chinnu said:
1 decade ago
train lost 12.5 min , convert into hrs = 12/60 = 1/5.
Remaining time = 4/5.
4/5*75 = 60.
As it is 50% then total speed of car is 120.
Remaining time = 4/5.
4/5*75 = 60.
As it is 50% then total speed of car is 120.
Lalit, said:
1 decade ago
Yes, Meetali T=d/s. The difference between the the time of car and train is 12. 5 min. i.e. we are calculating 75/x-75/3/2= 125/10*60.
Mancy said:
1 decade ago
Still I have a one confusion in my mind that why we are taking speed of a train as,
(50% of car+x) instead of 50% more i.e (50%+x).
(50% of car+x) instead of 50% more i.e (50%+x).
Helip said:
6 years ago
If we have to convert the minute in the second we will multiply with 60 then what does it mean in solution 125/10*60? Please tell me.
Pravin said:
1 decade ago
Time taken for car - time taken for train = 5/24 hr.
This equation is derived because both start at same time and end at same time.
This equation is derived because both start at same time and end at same time.
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