Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 16 of 35.
Reddy said:
1 decade ago
Hi friend that is not delay thats the time wasted by the train due to its stoppings if the train don't stop any where it will come first than car.
Solanki said:
1 decade ago
A is faster than B by 50 percent means, take a is 100 percent and more 20 percent faster than 100+20=120. And take B is 100 percent. Then 150/100.
Tharun kumar said:
4 years ago
Let the speed of the car be x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
(1)
Ravi kataria said:
9 years ago
As a train is much faster, then time difference must be [distance /train speed - distance /car speed =12.5min].
Then, how it does inversely?
Then, how it does inversely?
Rajan said:
1 decade ago
Say, the speed of the car be 1 km/hr (0. 5 +0. 5).
And if there is 50% increase in speed means (1 +0. 5) = 1. 5 km /hr.
That's how 3/2 came.
And if there is 50% increase in speed means (1 +0. 5) = 1. 5 km /hr.
That's how 3/2 came.
Mohit said:
2 decades ago
Hey look it say train travels 50% faster then car. Suppose car travels at x speed than train travels at 50x. So its 150/100 thats as a % age.
RAMJAN RAEEN said:
7 years ago
Can anyone explain to me how 75/X - 75/ (3x/2) = 12.5?
How the time is the same in both case car and train if a halt is not considering?
How the time is the same in both case car and train if a halt is not considering?
Chinnu said:
1 decade ago
train lost 12.5 min , convert into hrs = 12/60 = 1/5.
Remaining time = 4/5.
4/5*75 = 60.
As it is 50% then total speed of car is 120.
Remaining time = 4/5.
4/5*75 = 60.
As it is 50% then total speed of car is 120.
Anu said:
1 month ago
Most of people saying 1/2 instead of 3/2 is wrong.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
(8)
Lalit, said:
1 decade ago
Yes, Meetali T=d/s. The difference between the the time of car and train is 12. 5 min. i.e. we are calculating 75/x-75/3/2= 125/10*60.
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