Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 12 of 35.
Prasad chowdary said:
1 decade ago
Hi, @Arun to remove the decimal form 12.5. We multiply and divide 10.
(12.5*10)/10 = 125/10.
(12.5*10)/10 = 125/10.
GIS said:
1 decade ago
Let Speed of Car = x.
Train is 50% faster than car = x + x/2 = 3x/2.
Time difference = 12. 5 mins = 12. 5/60 hours = 125/600 = 5/24.
Distance = 75 km.
(Distance/Car speed) - (Distance/Train speed) = 12. 5 min = 5/24 hr.
(75/x) - (75/ (3/2x) ) = 5/24.
(75/x) - (150/3x) = 5/24.
25/x = 5/24.
X = (25*24) /5 = 120kmph.
Train is 50% faster than car = x + x/2 = 3x/2.
Time difference = 12. 5 mins = 12. 5/60 hours = 125/600 = 5/24.
Distance = 75 km.
(Distance/Car speed) - (Distance/Train speed) = 12. 5 min = 5/24 hr.
(75/x) - (75/ (3/2x) ) = 5/24.
(75/x) - (150/3x) = 5/24.
25/x = 5/24.
X = (25*24) /5 = 120kmph.
Anonymous said:
1 decade ago
Can someone explain this because I don't understand where all the fractions just popped out.
Karthik said:
1 decade ago
It says 50% more than Car's speed.
So if car's speed is X the train's speed is = (X+(50/100)X).
Hence (150/100)X.
So if car's speed is X the train's speed is = (X+(50/100)X).
Hence (150/100)X.
Vipul said:
1 decade ago
Can you explain how 125/10*6?
Jeeva said:
1 decade ago
I cannot understand this problem. Briefly explain.
Kulwant said:
1 decade ago
Simple:
Total Distance is 75kms.
Both train and car reached at same time in-spite of train having speed advantage of 50% over car i.e. 3/2.
Train lost this advantage due to 12.5 minutes stoppage.
That means this 12.5 minutes lost time equals to the speed advantage of train, had it not lost this time train would have reached earlier.
Therefore 12.5 *3 = 37.5 is the time taken by car to cover 75 kms.
Train took similar time to cover 75 distance stopping for 12.5 minutes. Had it not stopped it would have covered in 25 minutes (37.5-12.5 = 25).
S=d/t : Speed of car = 75/37.5 = 2 km per hour 2*60 = 120 km per hour.
Total Distance is 75kms.
Both train and car reached at same time in-spite of train having speed advantage of 50% over car i.e. 3/2.
Train lost this advantage due to 12.5 minutes stoppage.
That means this 12.5 minutes lost time equals to the speed advantage of train, had it not lost this time train would have reached earlier.
Therefore 12.5 *3 = 37.5 is the time taken by car to cover 75 kms.
Train took similar time to cover 75 distance stopping for 12.5 minutes. Had it not stopped it would have covered in 25 minutes (37.5-12.5 = 25).
S=d/t : Speed of car = 75/37.5 = 2 km per hour 2*60 = 120 km per hour.
Kamesh said:
1 decade ago
I don't understand this problem please solve easily.
Diwakar.I said:
1 decade ago
Can anyone explain how(150/100) came?
ANAND said:
1 decade ago
50% car faster means 100%+50% = 150.
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