Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 13 of 35.
Pramod said:
1 decade ago
50% faster means 1+1/2 = 3/2.
Ashish said:
1 decade ago
50% more than x means 50/100 + x = 150/100x.
Tarun said:
1 decade ago
Its easy guys OK I explain. Let speed of car is X.
Then speed of train is 150/100 multiply by X. Then after solve this 3/2X kmph.
Taking difference between car and train speed minutes.
= 75/x-75/3/2x = 12.5/60. Then speed of car means X is equal to 120 kmph.
Then speed of train is 150/100 multiply by X. Then after solve this 3/2X kmph.
Taking difference between car and train speed minutes.
= 75/x-75/3/2x = 12.5/60. Then speed of car means X is equal to 120 kmph.
Tarun said:
1 decade ago
Lost time is equal to difference between the time taken by car in X kmph and time taken by train in 150/100X kmph distance is same for both 75 kms.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
Gourav said:
1 decade ago
How to solve this question please tell me right formulas?
Sarath said:
1 decade ago
In one way it can be understood as difference of times is 12.5 min.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
Bhu said:
1 decade ago
Time of train+12.5 = Time of car.
Satyajit said:
1 decade ago
Train is faster so it should have been 75/(3/2*x)-75/x = 125/10*60.
Sowmiya.k said:
1 decade ago
Please anybody explain it briefly I can't understand.
Deepak said:
1 decade ago
Please explain in easy way can't understand please.
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