Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 35 of 35.
Deshik said:
5 months ago
Formula:
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
(52)
Lokesh said:
4 months ago
I am not understanding this question. Please explain to me.
(20)
ANom said:
3 months ago
Speed of car =2/3 the speed of the train.
ie Vc=2/3 Vt, therefore,
Time taken by car =3/2 Time taken by train ie.Tc=3/2 Tt.
Also,
Tc = Tt+15/60 hr ie. Tc = Tt + 1/4.
Therefore:
3/2 Tt = Tt+1/4
Tt = 1/2 = 0.5 hr.
Therefore, Tc = 0.75 = hr.
Distance = v x t.
75 km = Vc x 0.75,
Vc = 100km
Vt = 120.
ie Vc=2/3 Vt, therefore,
Time taken by car =3/2 Time taken by train ie.Tc=3/2 Tt.
Also,
Tc = Tt+15/60 hr ie. Tc = Tt + 1/4.
Therefore:
3/2 Tt = Tt+1/4
Tt = 1/2 = 0.5 hr.
Therefore, Tc = 0.75 = hr.
Distance = v x t.
75 km = Vc x 0.75,
Vc = 100km
Vt = 120.
(3)
Jithen M S said:
3 months ago
(The train can travel 50% faster than a car).
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
This means the train is travelling 1/2 time faster than the car, not 3/2 time faster.
Final Answer: Speed of the car = 100 kmph.
(6)
Abhishek S k said:
2 months ago
I didn't understand this, anyone please explain to me?
(7)
Anu said:
1 month ago
Most of people saying 1/2 instead of 3/2 is wrong.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
(8)
Deepana M said:
1 month ago
The train can travel 50% faster than a car. How to define 150 here? Please explain.
(3)
SHREYA said:
3 weeks ago
The speed of the car is x km/h.
The speed of the train = x + 50x/100,
= 150x/100,
= 3x/2 km/h.
The time taken by the car = 75/x.
The time taken by the train = 75/(3x/2).
The difference between them is 12.5 minutes.
75/x - 75/(3x/2) = 12.5 minutes.
To convert minutes to hours, divide the number by 60,
Therefore,
75/x - 75/(3x/2) = 12.5/60 hr,
75/x - 75/(3x/2) = 125/(10*60) hr,
75/x - 50/x = 5/24,
25/x = 5/24,
5x = 25*24.
x = 120 km/hr.
The speed of the train = x + 50x/100,
= 150x/100,
= 3x/2 km/h.
The time taken by the car = 75/x.
The time taken by the train = 75/(3x/2).
The difference between them is 12.5 minutes.
75/x - 75/(3x/2) = 12.5 minutes.
To convert minutes to hours, divide the number by 60,
Therefore,
75/x - 75/(3x/2) = 12.5/60 hr,
75/x - 75/(3x/2) = 125/(10*60) hr,
75/x - 50/x = 5/24,
25/x = 5/24,
5x = 25*24.
x = 120 km/hr.
(2)
BARATH M said:
2 weeks ago
Speed = Distance/Time.
Step 1 :
If x be the Speed of Car, then Speed of Train is x+50/100 = 3x/2.
According to this problem, Formula can be adjusted as Time = Distance/Speed.
Step 2 :
Time taken by Car => T1 = 75/x.
Time taken by Train => T2 = 75/ 3x/2 => T2 = 50/x.
Step 3 :
However, the train lost about 12.5 minutes while stopping at the stations.
Train's Total Time = Run time + Stopping time.
Convert 12.5 minutes in Hours as follows by 12.5 = 12.5/60
=>125/600 = 25/120 = 5/24.
Train's Total Time = 50/x + 5/24.
Step 4 :
Both reach at the same time, so T1 = T2.
Total time of Car = Total time of Train.
=> 75/x = 50/x + 5/24.
=> 75x - 50/x = 5/24.
=> 25/x = 5/24.
=> 120 = x.
Hence x = 120.
Step 1 :
If x be the Speed of Car, then Speed of Train is x+50/100 = 3x/2.
According to this problem, Formula can be adjusted as Time = Distance/Speed.
Step 2 :
Time taken by Car => T1 = 75/x.
Time taken by Train => T2 = 75/ 3x/2 => T2 = 50/x.
Step 3 :
However, the train lost about 12.5 minutes while stopping at the stations.
Train's Total Time = Run time + Stopping time.
Convert 12.5 minutes in Hours as follows by 12.5 = 12.5/60
=>125/600 = 25/120 = 5/24.
Train's Total Time = 50/x + 5/24.
Step 4 :
Both reach at the same time, so T1 = T2.
Total time of Car = Total time of Train.
=> 75/x = 50/x + 5/24.
=> 75x - 50/x = 5/24.
=> 25/x = 5/24.
=> 120 = x.
Hence x = 120.
(7)
Arun said:
2 weeks ago
I don't understand. Please explain me in detail.
(2)
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