Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 35 of 35.
Deshik said:
1 month ago
Formula:
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
Time = distance/speed.
Speed = distance/time.
Let speed of train = x.
Then speed of the car = x + (x(50)/100),
= x + x/2,
= 3x/2,
The time taken by the train = 75/x.
The time taken by the car = 75/(3x/2).
Difference between them = 12.5 minutes,
75/x - 75/(3x/2) = 125/10 minutes,
75/x - 75/(3x/2) = 125/(10*60) hr,
(225-150)/3x=125/600,
75/3x = 125/600,
25/x = 125/600,
x = (25*600)/125,
x = 120kmph.
(18)
Lokesh said:
3 weeks ago
I am not understanding this question. Please explain to me.
(7)
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