Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1
hours, it must travel at a speed of:
hours, it must travel at a speed of:Answer: Option
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
 Required speed = |
 |
1200 x | 3 |  km/hr |
= 720 km/hr. |
| 5 |
Discussion:
160 comments Page 3 of 16.
Sushma said:
12 months ago
720kmph is the correct form.
(9)
Vinay said:
3 years ago
1. d=? s=240 t=5.
240=d/5=1200;
s=1200/1.6666 [2/3=1.666666] = 720.
240=d/5=1200;
s=1200/1.6666 [2/3=1.666666] = 720.
(8)
Lokesh said:
4 years ago
Distance = 240 * 5=1200
1 +2 /3 = 5/3.
REQUIRED SPEED = (1200/5/3)
= (1200 * 3/5)
= 720KM/HR.
1 +2 /3 = 5/3.
REQUIRED SPEED = (1200/5/3)
= (1200 * 3/5)
= 720KM/HR.
(7)
Vaishnavi said:
4 years ago
How does 1 hr become 5/3?
(7)
Mathrasi Padmalatha said:
1 year ago
Let's calculate the speed:
Distance = Speed × Time.
Distance = 240 kmph × 5 hours = 1200 km.
To cover the same distance (1200 km) in 1 2/3 hours (or 5/3 hours):
Speed = Distance ÷ Time = 1200 km ÷ (5/3) hours = 1200 km × (3/5) hours = 720 kmph.
So, the correct answer is: D. 720 kmph
The plane needs to fly at a speed of 720 kmph to cover the same distance in 1 2/3 hours.
Distance = Speed × Time.
Distance = 240 kmph × 5 hours = 1200 km.
To cover the same distance (1200 km) in 1 2/3 hours (or 5/3 hours):
Speed = Distance ÷ Time = 1200 km ÷ (5/3) hours = 1200 km × (3/5) hours = 720 kmph.
So, the correct answer is: D. 720 kmph
The plane needs to fly at a speed of 720 kmph to cover the same distance in 1 2/3 hours.
(7)
Penumaka abhi said:
7 months ago
Given distance = 240.
Time = 5hours,
Dis = speed * time.
D = 240 * 5 = 1200.
Another dis=1 2 ÷ 3(mixed fraction is given)is converted into 5/3.
Dist= 1200÷5/3(divided by 5/3 is inverse isconverted 3/5).
D = 1200 ÷ 3/5 = 720.
1200 * 3/5 = 720.
Time = 5hours,
Dis = speed * time.
D = 240 * 5 = 1200.
Another dis=1 2 ÷ 3(mixed fraction is given)is converted into 5/3.
Dist= 1200÷5/3(divided by 5/3 is inverse isconverted 3/5).
D = 1200 ÷ 3/5 = 720.
1200 * 3/5 = 720.
(6)
Majji deepika said:
1 month ago
Given data:
Speed = 240km/hr.
t = 5hr.
By the way, to cover the same distance in another time t1 = 5/3.
Speed = distance/time.
dis = speed * time
dis = 240 * 5
dis = 1200km.
Speed = dis/time.
Speed = 1200/(5/3).
Speed = 3600/5 = 720km/hr.
Speed = 240km/hr.
t = 5hr.
By the way, to cover the same distance in another time t1 = 5/3.
Speed = distance/time.
dis = speed * time
dis = 240 * 5
dis = 1200km.
Speed = dis/time.
Speed = 1200/(5/3).
Speed = 3600/5 = 720km/hr.
(6)
Sam said:
2 years ago
1 (2/3) = (1*3(denominator)+3(numerator))/3 = 5/3.
(5)
Madhan said:
4 months ago
Thanks all for giving explanation.
(5)
DHIVYA J said:
2 months ago
600 m = 0.6 km => 600/1000,
5 min = 0.0833 hr => 5/60,
Speed = dist/time.
s = 0.6 /0.0833.
= 7.2.
5 min = 0.0833 hr => 5/60,
Speed = dist/time.
s = 0.6 /0.0833.
= 7.2.
(5)
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