Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:
300 kmph
360 kmph
600 kmph
720 kmph
Answer: Option
Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

Required speed = 1200 x 3 km/hr = 720 km/hr.
5

Discussion:
146 comments Page 1 of 15.

Rojob said:   8 months ago
Distance are same. So, we can write;
D1 = D2.
S1*T1 = S2*T2.
240*5 = S2*5/3,
S2 = 240*3,
S2 = 720kmph.
(40)

Pratik said:   1 year ago
Distance = speed × time.
D = 240kmph × 5hrs
D = 1200km.

Then,
Speed = d÷t.
S = 1200km ÷ 1 2/3 hrs.
S = 720kmph.
(27)

Vansh Chaudhary said:   1 year ago
Please explain me why 2/3 became 3/5 ?
(25)

Deepak gavade said:   1 year ago
Distance = S x T
= 240 * 5.
= 1200 KM/hr.
SPEED = D/T.
1 2/3 = (1*2+3)/3 = 5/3.
S =1200 / 5/3.
=1200 * 3/5.
= 720 Km/Hr.
(25)

Shakti said:   5 months ago
How We can write 1 2/3hours as 5/3 hours?

Please explain.
(21)

Buvaneswaran V said:   6 months ago
Give:
S1 = 240kmph.
T1 = 5 hours.
T2 = 1 1/2 hours = 5/3 hours.
D1=D2.

To Find:
S2 = ?
Solution:
D = S x T.
D1 = D2.
So, S1 x T1 = S2 x T2.
240 x 5 = S2 x 5/3.
S2 = (240 x 5 x 3 )/5.
(20)

Prashanth said:   9 months ago
1(2/3) is a mixed fraction.
= 1*2/3.

= Now we have to multiply denominator to 1 (1*3)
=3 + 2/3 = 5/3.
(19)

Shivi said:   2 years ago
How to simplify 1200 (5/3) ? Please explain.
(13)

Lath ... said:   3 years ago
Speed 1=240kmph, time1 = 5hr.
Speed2=x. Time2=5/3.

S1/S2 = T2/T1,
S2 = (240*5)/(5/3),
S2 = 240*3,
S2 = 720kmph.
(12)

Anisha said:   10 months ago
How does 2/3 become 3/5? Please explain to me.
(11)


Post your comments here:

Your comments will be displayed after verification.