# Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 2)

2.

An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:

Answer: Option

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]

Required speed = | 1200 x | 3 | km/hr | = 720 km/hr. | |

5 |

Discussion:

146 comments Page 1 of 15.
Rojob said:
8 months ago

Distance are same. So, we can write;

D1 = D2.

S1*T1 = S2*T2.

240*5 = S2*5/3,

S2 = 240*3,

S2 = 720kmph.

D1 = D2.

S1*T1 = S2*T2.

240*5 = S2*5/3,

S2 = 240*3,

S2 = 720kmph.

(40)

Pratik said:
1 year ago

Distance = speed × time.

D = 240kmph × 5hrs

D = 1200km.

Then,

Speed = d÷t.

S = 1200km ÷ 1 2/3 hrs.

S = 720kmph.

D = 240kmph × 5hrs

D = 1200km.

Then,

Speed = d÷t.

S = 1200km ÷ 1 2/3 hrs.

S = 720kmph.

(27)

Vansh Chaudhary said:
1 year ago

Please explain me why 2/3 became 3/5 ?

(25)

Deepak gavade said:
1 year ago

Distance = S x T

= 240 * 5.

= 1200 KM/hr.

SPEED = D/T.

1 2/3 = (1*2+3)/3 = 5/3.

S =1200 / 5/3.

=1200 * 3/5.

= 720 Km/Hr.

= 240 * 5.

= 1200 KM/hr.

SPEED = D/T.

1 2/3 = (1*2+3)/3 = 5/3.

S =1200 / 5/3.

=1200 * 3/5.

= 720 Km/Hr.

(25)

Shakti said:
5 months ago

How We can write 1 2/3hours as 5/3 hours?

Please explain.

Please explain.

(21)

Buvaneswaran V said:
6 months ago

Give:

S1 = 240kmph.

T1 = 5 hours.

T2 = 1 1/2 hours = 5/3 hours.

D1=D2.

To Find:

S2 = ?

Solution:

D = S x T.

D1 = D2.

So, S1 x T1 = S2 x T2.

240 x 5 = S2 x 5/3.

S2 = (240 x 5 x 3 )/5.

S1 = 240kmph.

T1 = 5 hours.

T2 = 1 1/2 hours = 5/3 hours.

D1=D2.

To Find:

S2 = ?

Solution:

D = S x T.

D1 = D2.

So, S1 x T1 = S2 x T2.

240 x 5 = S2 x 5/3.

S2 = (240 x 5 x 3 )/5.

(20)

Prashanth said:
9 months ago

1(2/3) is a mixed fraction.

= 1*2/3.

= Now we have to multiply denominator to 1 (1*3)

=3 + 2/3 = 5/3.

= 1*2/3.

= Now we have to multiply denominator to 1 (1*3)

=3 + 2/3 = 5/3.

(19)

Shivi said:
2 years ago

How to simplify 1200 (5/3) ? Please explain.

(13)

Lath ... said:
3 years ago

Speed 1=240kmph, time1 = 5hr.

Speed2=x. Time2=5/3.

S1/S2 = T2/T1,

S2 = (240*5)/(5/3),

S2 = 240*3,

S2 = 720kmph.

Speed2=x. Time2=5/3.

S1/S2 = T2/T1,

S2 = (240*5)/(5/3),

S2 = 240*3,

S2 = 720kmph.

(12)

Anisha said:
10 months ago

How does 2/3 become 3/5? Please explain to me.

(11)

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