Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1
hours, it must travel at a speed of:
hours, it must travel at a speed of:Answer: Option
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1
hours as 5/3 hours]
Required speed = |
![]() |
1200 x | 3 | km/hr |
= 720 km/hr. |
| 5 |
Discussion:
162 comments Page 3 of 17.
Buvaneswaran V said:
2 years ago
Give:
S1 = 240kmph.
T1 = 5 hours.
T2 = 1 1/2 hours = 5/3 hours.
D1=D2.
To Find:
S2 = ?
Solution:
D = S x T.
D1 = D2.
So, S1 x T1 = S2 x T2.
240 x 5 = S2 x 5/3.
S2 = (240 x 5 x 3 )/5.
S1 = 240kmph.
T1 = 5 hours.
T2 = 1 1/2 hours = 5/3 hours.
D1=D2.
To Find:
S2 = ?
Solution:
D = S x T.
D1 = D2.
So, S1 x T1 = S2 x T2.
240 x 5 = S2 x 5/3.
S2 = (240 x 5 x 3 )/5.
(26)
Jeswin said:
2 years ago
Please Explain how and why the reciprocal became 5/3 to 3/5. Someone, could you explain it?
(14)
Rojob said:
2 years ago
Distance are same. So, we can write;
D1 = D2.
S1*T1 = S2*T2.
240*5 = S2*5/3,
S2 = 240*3,
S2 = 720kmph.
D1 = D2.
S1*T1 = S2*T2.
240*5 = S2*5/3,
S2 = 240*3,
S2 = 720kmph.
(52)
Chandra sekhar said:
2 years ago
How 1200/5/3 became 1200/3/5? Please Explain me.
(13)
Prashanth said:
2 years ago
1(2/3) is a mixed fraction.
= 1*2/3.
= Now we have to multiply denominator to 1 (1*3)
=3 + 2/3 = 5/3.
= 1*2/3.
= Now we have to multiply denominator to 1 (1*3)
=3 + 2/3 = 5/3.
(23)
Vaishnavi Kasana said:
3 years ago
In question it's given in mixed fraction, therefore it will be converted into fraction i.e 5/3 hrs.
(3*1)+2=5.
Fraction = 5/3hrs.
(3*1)+2=5.
Fraction = 5/3hrs.
(10)
Anisha said:
3 years ago
How does 2/3 become 3/5? Please explain to me.
(12)
Sam said:
3 years ago
1 (2/3) = (1*3(denominator)+3(numerator))/3 = 5/3.
(5)
Deepak gavade said:
3 years ago
Distance = S x T
= 240 * 5.
= 1200 KM/hr.
SPEED = D/T.
1 2/3 = (1*2+3)/3 = 5/3.
S =1200 / 5/3.
=1200 * 3/5.
= 720 Km/Hr.
= 240 * 5.
= 1200 KM/hr.
SPEED = D/T.
1 2/3 = (1*2+3)/3 = 5/3.
S =1200 / 5/3.
=1200 * 3/5.
= 720 Km/Hr.
(25)
Pratik said:
3 years ago
Distance = speed × time.
D = 240kmph × 5hrs
D = 1200km.
Then,
Speed = d÷t.
S = 1200km ÷ 1 2/3 hrs.
S = 720kmph.
D = 240kmph × 5hrs
D = 1200km.
Then,
Speed = d÷t.
S = 1200km ÷ 1 2/3 hrs.
S = 720kmph.
(27)
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Required speed =
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