Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1
hours, it must travel at a speed of:
hours, it must travel at a speed of:Answer: Option
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
 Required speed = |
 |
1200 x | 3 |  km/hr |
= 720 km/hr. |
| 5 |
Discussion:
164 comments Page 4 of 17.
Deepak gavade said:
3 years ago
Distance = S x T
= 240 * 5.
= 1200 KM/hr.
SPEED = D/T.
1 2/3 = (1*2+3)/3 = 5/3.
S =1200 / 5/3.
=1200 * 3/5.
= 720 Km/Hr.
= 240 * 5.
= 1200 KM/hr.
SPEED = D/T.
1 2/3 = (1*2+3)/3 = 5/3.
S =1200 / 5/3.
=1200 * 3/5.
= 720 Km/Hr.
(25)
Pratik said:
3 years ago
Distance = speed × time.
D = 240kmph × 5hrs
D = 1200km.
Then,
Speed = d÷t.
S = 1200km ÷ 1 2/3 hrs.
S = 720kmph.
D = 240kmph × 5hrs
D = 1200km.
Then,
Speed = d÷t.
S = 1200km ÷ 1 2/3 hrs.
S = 720kmph.
(27)
Vinay said:
4 years ago
1. d=? s=240 t=5.
240=d/5=1200;
s=1200/1.6666 [2/3=1.666666] = 720.
240=d/5=1200;
s=1200/1.6666 [2/3=1.666666] = 720.
(8)
Vansh Chaudhary said:
4 years ago
Please explain me why 2/3 became 3/5 ?
(26)
Shivi said:
4 years ago
How to simplify 1200 (5/3) ? Please explain.
(13)
Bharath kumar said:
4 years ago
How does 1hr become 5/3?
(4)
Vaishnavi said:
5 years ago
How does 1 hr become 5/3?
(7)
Lath ... said:
5 years ago
Speed 1=240kmph, time1 = 5hr.
Speed2=x. Time2=5/3.
S1/S2 = T2/T1,
S2 = (240*5)/(5/3),
S2 = 240*3,
S2 = 720kmph.
Speed2=x. Time2=5/3.
S1/S2 = T2/T1,
S2 = (240*5)/(5/3),
S2 = 240*3,
S2 = 720kmph.
(12)
Aditi said:
5 years ago
Why 240 x 5?
(1)
Lokesh said:
5 years ago
Distance = 240 * 5=1200
1 +2 /3 = 5/3.
REQUIRED SPEED = (1200/5/3)
= (1200 * 3/5)
= 720KM/HR.
1 +2 /3 = 5/3.
REQUIRED SPEED = (1200/5/3)
= (1200 * 3/5)
= 720KM/HR.
(7)
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