Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:
300 kmph
360 kmph
600 kmph
720 kmph
Answer: Option
Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

Required speed = 1200 x 3 km/hr = 720 km/hr.
5

Discussion:
160 comments Page 4 of 16.

Shivi said:   3 years ago
How to simplify 1200 (5/3) ? Please explain.
(13)

Bharath kumar said:   3 years ago
How does 1hr become 5/3?
(4)

Vaishnavi said:   4 years ago
How does 1 hr become 5/3?
(7)

Lath ... said:   4 years ago
Speed 1=240kmph, time1 = 5hr.
Speed2=x. Time2=5/3.

S1/S2 = T2/T1,
S2 = (240*5)/(5/3),
S2 = 240*3,
S2 = 720kmph.
(12)

Aditi said:   4 years ago
Why 240 x 5?
(1)

Lokesh said:   4 years ago
Distance = 240 * 5=1200
1 +2 /3 = 5/3.

REQUIRED SPEED = (1200/5/3)
= (1200 * 3/5)
= 720KM/HR.
(7)

Vaidik said:   4 years ago
According to the tri-rashi method.

5hours ----------->240km/h.
5/3hours ---------> (?).

5 x 240/5 x3 =80kmph.

I know this is wrong but speed should increase here because time is decreasing but I want to know why this method is not applicable here. Please can anyone help me to solve this?
(2)

Ajai said:   4 years ago
Speed = distance /time methods is used here.
(3)

Siddhesh said:   4 years ago
Can you tell me 5/3 means how many minutes?

Saran said:   5 years ago
Distance= 240x5= 1200km.

speed = distance/ time.
=1200/(5/3).
=(1200 x 3)/5,
=3600/5,
=720km/h.
(2)


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