Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 3)
3.
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Answer: Option
Explanation:
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
| Then, 10x = 4y or y = | 5 | x. |
| 2 |
15x + 2y = 4000
 15x + 2 x |
5 | x = 4000 |
| 2 |
20x = 4000
x = 200.
| So, y = |  |
5 | x 200 |  |
= 500. |
| 2 |
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Discussion:
32 comments Page 4 of 4.
Anna John said:
2 years ago
Chair- x, table-y.
10x= 2y.
when you divide them by 2, you get:
5x = 2y -----------> (1)
15x+2y= 4000
15x+5x= 4000,
20x= 4000.
x= 4000/20= 200.
y=5x/2= 5*200/2= 500.
The total of 12 chairs and 3 tables is:
12 * 200 + 3 * 500 = 3900.
10x= 2y.
when you divide them by 2, you get:
5x = 2y -----------> (1)
15x+2y= 4000
15x+5x= 4000,
20x= 4000.
x= 4000/20= 200.
y=5x/2= 5*200/2= 500.
The total of 12 chairs and 3 tables is:
12 * 200 + 3 * 500 = 3900.
(5)
Nayshi said:
4 months ago
10 chairs X =4 Tables Y.
Then, 10X =4Y.
Divide both sides by 2.
5x = 2y came,
5x multiplication equal to reciprocal divide & Keep it;
X in the left side only take 5,
Like this X = 5/2 Y.
Then, 10X =4Y.
Divide both sides by 2.
5x = 2y came,
5x multiplication equal to reciprocal divide & Keep it;
X in the left side only take 5,
Like this X = 5/2 Y.
(2)
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