Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 3)
3.
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
Answer: Option
Explanation:
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
| Then, 10x = 4y or y = | 5 | x. |
| 2 |
15x + 2y = 4000
 15x + 2 x |
5 | x = 4000 |
| 2 |
20x = 4000
x = 200.
| So, y = |  |
5 | x 200 |  |
= 500. |
| 2 |
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Discussion:
32 comments Page 4 of 4.
Dilip said:
1 decade ago
15C+2T=4000
30C+4T=8000
10C=4T
30C+10C=8000
40C=8000
C=200
15(200)+2T=4000
3000+2T=4000
2T=1000
T=500
12(200)+3(500)=3900
30C+4T=8000
10C=4T
30C+10C=8000
40C=8000
C=200
15(200)+2T=4000
3000+2T=4000
2T=1000
T=500
12(200)+3(500)=3900
Sandeep said:
1 decade ago
Easy way: If 10C=4T then 5C=2T......(1)
given 15C+2T=4000
using (1) we get C=200 & T=500
Hence we can find remaining...
given 15C+2T=4000
using (1) we get C=200 & T=500
Hence we can find remaining...
(1)
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