Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 1)
1.
A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Answer: Option
Explanation:
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
Discussion:
77 comments Page 3 of 8.
Anurag said:
9 years ago
What if ratios are also given like 3:4:5 then how to solve it?
Chaithra said:
3 years ago
Thanks for explaining @Ramesh.
Kothimerla ashok said:
9 years ago
Let no of 5 rupees note be x.
Then
The no of 10 rupees notes will be (70-x).
Therefore,
5x - 10(70-x) = 590,
x = 22.
Therefore, num of 10 rupees notes is 70 - 22 = 48.
Then
The no of 10 rupees notes will be (70-x).
Therefore,
5x - 10(70-x) = 590,
x = 22.
Therefore, num of 10 rupees notes is 70 - 22 = 48.
Khushboo said:
5 years ago
Thanks all for the explanation.
Jeevana said:
9 years ago
Thank you @Ramesh.
Jeevavignesh said:
9 years ago
Thanks for al your explanation.
Sunil said:
8 years ago
A man has 6565 in the denomination of Rs 5notes Rs10notes Rs50 the number of notes of each 3 denomination is equal with him the total number of note he has. Please solve it.
Tuan Ossen said:
8 years ago
Thanks for all your explanations.
Anu said:
8 years ago
Thank you for the explanation.
Subin said:
8 years ago
Nice explanation. Thanks.
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