Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 5)
5.
In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:
Answer: Option
Explanation:
| Quantity of milk = |  |
60 x | 2 |  litres = 40 litres. |
| 3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
| Then, milk : water = | |
40 | |
. |
| 20 + x |
| Now, | |
40 | |
= | 1 |
| 20 + x | 2 |
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
Discussion:
149 comments Page 2 of 15.
Mehbub said:
2 years ago
So the ratio using;
n = a + b/c + d.
2 + 1/1 + 2 = 1.
Q = 1
Therefore,
1*60 = 60litres.
n = a + b/c + d.
2 + 1/1 + 2 = 1.
Q = 1
Therefore,
1*60 = 60litres.
(14)
Swetha said:
5 years ago
m:w=2:1
m+w=60
2x+x-=60
x=20.
m=40 w=20.
Added water be y.
40:(20+y) = 1:2.
On cross multiplication
y=60.
m+w=60
2x+x-=60
x=20.
m=40 w=20.
Added water be y.
40:(20+y) = 1:2.
On cross multiplication
y=60.
(13)
Madhur Nanhorya said:
1 year ago
Here, we can't just add different quantities of water.
So from the first case we got milk = 40 litres and water = 20 litres, now to make the ratio from 2:1 to 1:2.
So, the Amount of milk in the new mixture = 2 x milk in the old mixture = 2 x 40 litres = 80 litres, so the difference in water quantities = 80 - 20 = 60 litres.
So from the first case we got milk = 40 litres and water = 20 litres, now to make the ratio from 2:1 to 1:2.
So, the Amount of milk in the new mixture = 2 x milk in the old mixture = 2 x 40 litres = 80 litres, so the difference in water quantities = 80 - 20 = 60 litres.
(11)
Souvik das said:
4 years ago
The ratio of milk and water in 60L is;
m=2.
w=1 (2+1)=3,
milk = 2/3, water=1/3.
milk in 60L = 2/3 * 60= 40L.
water in 60L = 1/3 * 60= 20L,
40:(20+60)=4:8= 1:2.
m=2.
w=1 (2+1)=3,
milk = 2/3, water=1/3.
milk in 60L = 2/3 * 60= 40L.
water in 60L = 1/3 * 60= 20L,
40:(20+60)=4:8= 1:2.
(9)
Aiswarya said:
9 months ago
Orginal mixture = 60l.
Milk: water = 2:1.
Milk = 60 * 2/3 = 40l.
Water = 60 * 1/3 = 20l.
New mixture ratio = 1:2.
40lmilk + (20+x)l water,
40:20 + x = 1:2,
20 + x = 80,
X = 60.
Milk: water = 2:1.
Milk = 60 * 2/3 = 40l.
Water = 60 * 1/3 = 20l.
New mixture ratio = 1:2.
40lmilk + (20+x)l water,
40:20 + x = 1:2,
20 + x = 80,
X = 60.
(9)
Sony said:
5 years ago
Total = 60.
Milk: water 2:1 means 40:20.
60*40/20 = 120.
1:2 new ratio, then water added
120 = 40:80.
Then,
120*40/80 = 60.
Thank you.
Milk: water 2:1 means 40:20.
60*40/20 = 120.
1:2 new ratio, then water added
120 = 40:80.
Then,
120*40/80 = 60.
Thank you.
(8)
Kuldeep said:
1 year ago
Its very simple one drum of sixty litter quantity only;
1 . 2:1 that means 40 : 20 -40 milk and 20 water
2. 1:2 that mean 20:40-20milk and 40 water.
If we add both 60 kg water, further we want to it be 0:3 only 60 litter water.
1 . 2:1 that means 40 : 20 -40 milk and 20 water
2. 1:2 that mean 20:40-20milk and 40 water.
If we add both 60 kg water, further we want to it be 0:3 only 60 litter water.
(7)
Chith said:
5 years ago
The initial quantity of milk=(2/3)*90 = 60,
Initial quantity of water=(1/3)*90 = 30,
If the ratio is to be 2:3 the water to be added;
(60÷(30+x)) = 2/3,
X = 60.
Initial quantity of water=(1/3)*90 = 30,
If the ratio is to be 2:3 the water to be added;
(60÷(30+x)) = 2/3,
X = 60.
(6)
Thanglalmawn Gangte said:
2 years ago
By Using the relation,
X(ad-bc)/c(a+b)
We get,
= 60(2×2-1×1)/1(2+1),
= 60(4-1)/3,
= 60.
X(ad-bc)/c(a+b)
We get,
= 60(2×2-1×1)/1(2+1),
= 60(4-1)/3,
= 60.
(6)
Gokul said:
2 months ago
2x + x = 60,
x = 20.
Then milk =2*20 = 40,
water = 20.
New ratio=sum of mixtures(new)
1:2 = 40+20+x,
3x = 60+x,
x = 30.
Now, water to be added = 2 * 20 = 60.
x = 20.
Then milk =2*20 = 40,
water = 20.
New ratio=sum of mixtures(new)
1:2 = 40+20+x,
3x = 60+x,
x = 30.
Now, water to be added = 2 * 20 = 60.
(6)
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