Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 5)
5.
In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:
Answer: Option
Explanation:
Quantity of milk = | ![]() |
60 x | 2 | ![]() |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ![]() |
40 | ![]() |
. |
20 + x |
Now, | ![]() |
40 | ![]() |
= | 1 |
20 + x | 2 |
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
Discussion:
135 comments Page 1 of 14.
Aditya said:
6 months ago
The ratio of milk to water is given as: 2:1.
Let us assume a quantity of milk is 2x ans water is x.
Therefore ,
2x + x = 60 liters (Total mixture).
3x = 60
x = 20 --------(1)
Now milk is 2x therefore 2*20 = 40 liters is milk.
Now new water is added therefore x becomes (20 + x),
now new ration is given 40 /(20+x) = 1/2,
80 = 20 + x.
x = 60 Liters.
Let us assume a quantity of milk is 2x ans water is x.
Therefore ,
2x + x = 60 liters (Total mixture).
3x = 60
x = 20 --------(1)
Now milk is 2x therefore 2*20 = 40 liters is milk.
Now new water is added therefore x becomes (20 + x),
now new ration is given 40 /(20+x) = 1/2,
80 = 20 + x.
x = 60 Liters.
(4)
Nagasheshu said:
10 months ago
60 lit, 2:1.
2x +1x = 60 lit,
3x = 60,
x = 60/3,
x = 20 lit.
2x +1x = 60 lit,
3x = 60,
x = 60/3,
x = 20 lit.
Souvik das said:
12 months ago
The ratio of milk and water in 60L is;
m=2.
w=1 (2+1)=3,
milk = 2/3, water=1/3.
milk in 60L = 2/3 * 60= 40L.
water in 60L = 1/3 * 60= 20L,
40:(20+60)=4:8= 1:2.
m=2.
w=1 (2+1)=3,
milk = 2/3, water=1/3.
milk in 60L = 2/3 * 60= 40L.
water in 60L = 1/3 * 60= 20L,
40:(20+60)=4:8= 1:2.
Kushal said:
1 year ago
@All.
Simply the solution is;
Mixture = 60 litre.
The ratio is 2: 1 , so milk:water=40:20.
New ratio= 1: 2 , means milk : water should be 40:80.
Water in the new mixture should be 80.
Less water already in the mix 20.
Water to be added now is 60.
Simply the solution is;
Mixture = 60 litre.
The ratio is 2: 1 , so milk:water=40:20.
New ratio= 1: 2 , means milk : water should be 40:80.
Water in the new mixture should be 80.
Less water already in the mix 20.
Water to be added now is 60.
(1)
Swetha said:
2 years ago
m:w=2:1
m+w=60
2x+x-=60
x=20.
m=40 w=20.
Added water be y.
40:(20+y) = 1:2.
On cross multiplication
y=60.
m+w=60
2x+x-=60
x=20.
m=40 w=20.
Added water be y.
40:(20+y) = 1:2.
On cross multiplication
y=60.
Chith said:
2 years ago
The initial quantity of milk=(2/3)*90 = 60,
Initial quantity of water=(1/3)*90 = 30,
If the ratio is to be 2:3 the water to be added;
(60÷(30+x)) = 2/3,
X = 60.
Initial quantity of water=(1/3)*90 = 30,
If the ratio is to be 2:3 the water to be added;
(60÷(30+x)) = 2/3,
X = 60.
Dileep said:
2 years ago
40/20+x = 1/2.
Cross multiple;
80 = 20 + x.
x = 60.
Cross multiple;
80 = 20 + x.
x = 60.
Sony said:
2 years ago
Total = 60.
Milk: water 2:1 means 40:20.
60*40/20 = 120.
1:2 new ratio, then water added
120 = 40:80.
Then,
120*40/80 = 60.
Thank you.
Milk: water 2:1 means 40:20.
60*40/20 = 120.
1:2 new ratio, then water added
120 = 40:80.
Then,
120*40/80 = 60.
Thank you.
Shreyaa said:
2 years ago
40/20+x=1/2 anyone can solve it?
Sukri said:
2 years ago
Initially we have 60lt in the ratio 2:1.
i.e: 40lt milk & 20lt water.
Think logically,
Our condition is to make the ratio as 1:2.
i.e: 40lt milk & 80lt water.
Then 40 : 80 it will become 1:2.
So, the required amount of water will be 80 - 20 (i.e: final quantity - initial quantity -> then we can get req amount of water to make the ratio as 1:2).
i.e: 40lt milk & 20lt water.
Think logically,
Our condition is to make the ratio as 1:2.
i.e: 40lt milk & 80lt water.
Then 40 : 80 it will become 1:2.
So, the required amount of water will be 80 - 20 (i.e: final quantity - initial quantity -> then we can get req amount of water to make the ratio as 1:2).
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