# Aptitude - Ratio and Proportion

Exercise : Ratio and Proportion - General Questions

- Ratio and Proportion - Formulas
- Ratio and Proportion - General Questions

1.

A and B together have Rs. 1210. If of A's amount is equal to of B's amount, how much amount does B have?

Answer: Option

Explanation:

4 | A | = | 2 | B | |

15 | 5 |

A = | 2 | x | 15 | B | |

5 | 4 |

A = | 3 | B |

2 |

A | = | 3 | |

B | 2 |

A : B = 3 : 2.

B's share = Rs. | 1210 x | 2 | = Rs. 484. | ||

5 |

2.

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

Answer: Option

Explanation:

Let the third number be *x*.

Then, first number = 120% of x = |
120x |
= | 6x |

100 | 5 |

Second number = 150% of x = |
150x |
= | 3x |

100 | 2 |

Ratio of first two numbers = | 6x |
: | 3x |
= 12x : 15x = 4 : 5. |
||

5 | 2 |

3.

A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?

Answer: Option

Explanation:

Let the shares of A, B, C and D be Rs. 5*x*, Rs. 2*x*, Rs. 4*x* and Rs. 3*x* respectively.

Then, 4*x* - 3*x* = 1000

*x* = 1000.

B's share = Rs. 2*x* = Rs. (2 x 1000) = Rs. 2000.

4.

Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?

Answer: Option

Explanation:

Originally, let the number of seats for Mathematics, Physics and Biology be 5*x*, 7*x* and 8*x* respectively.

Number of increased seats are (140% of 5*x*), (150% of 7*x*) and (175% of 8*x*).

140 | x 5x |
, | 150 | x 7x |
and | 175 | x 8x |
|||||||

100 | 100 | 100 |

7x, |
21x |
and 14x. |

2 |

The required ratio = 7x : |
21x |
: 14x |

2 |

14*x* : 21*x* : 28*x*

2 : 3 : 4.

5.

In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:

Answer: Option

Explanation:

Quantity of milk = | 60 x | 2 | litres = 40 litres. | |

3 |

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be *x* litres.

Then, milk : water = | 40 | . | ||

20 + x |

Now, | 40 | = | 1 | ||

20 + x |
2 |

20 + *x* = 80

*x* = 60.

Quantity of water to be added = 60 litres.

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