Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 2)
2.
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Answer: Option
Explanation:
Let the third number be x.
Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
Ratio of first two numbers = | 6x | : | 3x | = 12x : 15x = 4 : 5. | ||
5 | 2 |
Discussion:
130 comments Page 1 of 13.
Ramkumar P said:
1 month ago
120/100 : 150/100.
120 : 150,
4 : 5.
120 : 150,
4 : 5.
(6)
FOUAD said:
2 months ago
Let A = 1.2 X.
Let B = 1.5 X.
A/B = 1.2X/1.5X,
A/B = 4/5,
A:B = 4:5.
Let B = 1.5 X.
A/B = 1.2X/1.5X,
A/B = 4/5,
A:B = 4:5.
(6)
Suhel Patel said:
2 months ago
Let, the third number is 100.
now the first is 20% more than 3rd number = 120.
and the second number is 50% more than the 3rd number = 150.
Then, 1 num : 2 num.
120 : 150.
So, the answer is 4:5.
now the first is 20% more than 3rd number = 120.
and the second number is 50% more than the 3rd number = 150.
Then, 1 num : 2 num.
120 : 150.
So, the answer is 4:5.
(29)
Diyaa said:
3 months ago
Let the third number be denoted as x.
The first number is 20% more than x.
Therefore, the first number is: x+0.2x = 1.2x.
The second number is 50% more than x.
Therefore, the second number is x+0.5x = 1.5x.
We need to find the ratio of the first to the second number: 1.2x/1.5x.
The x terms cancel out, simplifying the ratio into 4/5.
So, the Answer is 4/5.
The first number is 20% more than x.
Therefore, the first number is: x+0.2x = 1.2x.
The second number is 50% more than x.
Therefore, the second number is x+0.5x = 1.5x.
We need to find the ratio of the first to the second number: 1.2x/1.5x.
The x terms cancel out, simplifying the ratio into 4/5.
So, the Answer is 4/5.
(5)
Apeksha Puppalwar said:
4 months ago
Consider third number as X.
The question say's that 1st number is 20% more than the third number means a = 20%X + X.
Similarly,
Second number = b = 50%X + X,
a/b = 0.2X + X/0.5X + X,
= X(0.2 + 1)/X(0.5 + 1),
= 1.2/1.5.
= 4/5.
The question say's that 1st number is 20% more than the third number means a = 20%X + X.
Similarly,
Second number = b = 50%X + X,
a/b = 0.2X + X/0.5X + X,
= X(0.2 + 1)/X(0.5 + 1),
= 1.2/1.5.
= 4/5.
(6)
Vin said:
4 months ago
Thanks everyone for explaining the answer.
(3)
Ujjwal kumar said:
5 months ago
Let the third number be 100.
1st number is 120, and the second number 150.
Then the ratio of 120 and 150 will be 4:5.
1st number is 120, and the second number 150.
Then the ratio of 120 and 150 will be 4:5.
(41)
Ramya D said:
6 months ago
Assume the third number as X,
so x+20/100 // x+50/100,
120x/100 // 150x/100,
6/5 : 3/2 => 6 * 2 : 5 * 3 => 4 : 5.
so x+20/100 // x+50/100,
120x/100 // 150x/100,
6/5 : 3/2 => 6 * 2 : 5 * 3 => 4 : 5.
(23)
Bagavathsingh said:
8 months ago
Third number = x
First number = 20x/100
Second number = 50x/100
Assuming x = 10.
Put the value'
= (20*10/100) + 10 = 12,
= (50*10/100) + 10 = 15,
= 12:15.
= 4:5.
First number = 20x/100
Second number = 50x/100
Assuming x = 10.
Put the value'
= (20*10/100) + 10 = 12,
= (50*10/100) + 10 = 15,
= 12:15.
= 4:5.
(24)
Lokesh said:
8 months ago
@Sujaathasree.
If the percentage increases or mentioned directly we can take it as 100+20% since the percentage increases directly to 100 and if loss or decrease by 20% then we should do 100-20%.
If the percentage increases or mentioned directly we can take it as 100+20% since the percentage increases directly to 100 and if loss or decrease by 20% then we should do 100-20%.
(17)
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