Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 2)
2.
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Answer: Option
Explanation:
Let the third number be x.
Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
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6x | : | 3x | ![]() |
= 12x : 15x = 4 : 5. |
5 | 2 |
Discussion:
134 comments Page 6 of 14.
Kushi said:
1 decade ago
Thanks sathi.
Nidhi said:
1 decade ago
Ganapathy you are awsome.
Richa said:
1 decade ago
Sathi method is very good.
GNANESWAR said:
1 decade ago
Sathi concept is perfect.
Enigma said:
1 decade ago
How can one add a costant n a variable?
dats wrong..!
its simply..
x=20/100*z+z
y=50/100*z +z
if z is taken as the third no.. :)
dats wrong..!
its simply..
x=20/100*z+z
y=50/100*z +z
if z is taken as the third no.. :)
Sasa said:
1 decade ago
Ali and ganapathy good work :).
Gitty said:
1 decade ago
If you take x as 100 we will get 4:5..agreed. What is the problem in taking x as a variable itself..? Then the answer become 2:5,right..? could anyone please explain ?
Satish rathnam said:
1 decade ago
ok mr.gitty take 'x' only. u will get 4:5
=>1st number :2nd number
=> 20% more than X : 50% more than X
=> now cancel "more than X" on both sides
=> 20% : 50 %
=> 1.2 : 1.5
=> 4:5
=>1st number :2nd number
=> 20% more than X : 50% more than X
=> now cancel "more than X" on both sides
=> 20% : 50 %
=> 1.2 : 1.5
=> 4:5
Prashant said:
1 decade ago
20% of 'x' + 'x' (20% more than third number)
=> 120/100x
=> 120/100x
Yash said:
1 decade ago
I understand the method but why we add 100 in 20% and 50%. If we take third no is x so how a variable is added in 20% and 50%. But satish your method is simple and understood to me.
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