Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 2)
2.
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Answer: Option
Explanation:
Let the third number be x.
| Then, first number = 120% of x = | 120x | = | 6x |
| 100 | 5 |
| Second number = 150% of x = | 150x | = | 3x |
| 100 | 2 |
 Ratio of first two numbers = |
 |
6x | : | 3x |  |
= 12x : 15x = 4 : 5. |
| 5 | 2 |
Discussion:
134 comments Page 14 of 14.
Morepankh said:
5 years ago
ATP,
1st no., Is 20% more than 3rd no.
Let 3rd no., be x;
Then, 1st no.,=(20/100)*x+x.
2nd no.,=(50/100)*x+x.
Finally,
1st = 120x/100.
2nd = 150x/100.
3rd = x.
Ratio required = 120x/100:150x/100.
= 4:5.
1st no., Is 20% more than 3rd no.
Let 3rd no., be x;
Then, 1st no.,=(20/100)*x+x.
2nd no.,=(50/100)*x+x.
Finally,
1st = 120x/100.
2nd = 150x/100.
3rd = x.
Ratio required = 120x/100:150x/100.
= 4:5.
Shalini e said:
5 years ago
Thank you all for explaining the concept.
Simran said:
5 years ago
Let c is 1,
then,
first = 1 + 0.20*1,
second = 1 + 0.50*1,
ratio = 4:5.
then,
first = 1 + 0.20*1,
second = 1 + 0.50*1,
ratio = 4:5.
Surya said:
4 years ago
Thanks for explaining @Ganapathy.
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