Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 15)
15.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
| Then, sum of their values = Rs. |  |
25x | + | 10 x 2x | + | 5 x 3x |  |
= Rs. | 60x |
| 100 | 100 | 100 | 100 |
 |
60x | = 30 |  x = |
30 x 100 | = 50. |
| 100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Discussion:
117 comments Page 10 of 12.
Pooja said:
8 years ago
A bag contains Rs 5 coins, Rs 2 coins with total amount number of coins being 52, and the total amount is 125. The number of five rupees and two rupee coins are 37. The number of Rs 5coins are?
Can anyone answer it?
Can anyone answer it?
Sunny said:
8 years ago
Why are we taking 2, 2x, 3x why not x, y, z?
Nagamani said:
8 years ago
Even I am not getting clarity. Can any one give the correct explanation for this, please?
Soham said:
8 years ago
Why we multiping coin value like 25*x/100?
Jalapathy said:
8 years ago
25p * 1:10p*2:5p*3=25:20:15.
Total coins =25+20+15=60
We convert Rs.30 by Paisa because given values are Paisa.
30*100=3000
Formula
What is asked, given value/what is given
5p in bag?
So
15*3000/60 =750
In our final conclusion is total 5p coin in bag
750/5p. =150 ans.
Total coins =25+20+15=60
We convert Rs.30 by Paisa because given values are Paisa.
30*100=3000
Formula
What is asked, given value/what is given
5p in bag?
So
15*3000/60 =750
In our final conclusion is total 5p coin in bag
750/5p. =150 ans.
Sandeep said:
8 years ago
Ans should be 300.
1x+2x+3x=30
X=5
5p coinz = 15rs
15rs = 300 coinz of 5paise.
1x+2x+3x=30
X=5
5p coinz = 15rs
15rs = 300 coinz of 5paise.
Ello said:
8 years ago
25p,10p,5p = 1:2:3.
1/6:2/6:3/6,
30* 1/6=5,
30*2/6=10,
30*3/6=15,
5:10:15=50:100:150.
1/6:2/6:3/6,
30* 1/6=5,
30*2/6=10,
30*3/6=15,
5:10:15=50:100:150.
Jess said:
7 years ago
25:10:5= cancel by 5 you get 5:2:1.
Add 5+2+1=8 and add all the coins 25+10+5=40.
40/8=5.
5*30(30p given) =150.
Add 5+2+1=8 and add all the coins 25+10+5=40.
40/8=5.
5*30(30p given) =150.
Surya teja said:
7 years ago
x+2x+3x=300ps.
6x=300ps,
X=50ps.
Then 5ps coins=3*50,
=150.
6x=300ps,
X=50ps.
Then 5ps coins=3*50,
=150.
Sourabh Thakur said:
7 years ago
According to me;
By solving by N.R.V.
25p ------- 10p ------- 5p -------25p+10p+5p
n- 1 ------- 2 ------- 3
r- 1/1 ------- 1/2 ------- 1/3
v- 1 ------- 1 ------- 1 =>3*10=30.
So, the total no coin of 5p are 3*10=30.
By solving by N.R.V.
25p ------- 10p ------- 5p -------25p+10p+5p
n- 1 ------- 2 ------- 3
r- 1/1 ------- 1/2 ------- 1/3
v- 1 ------- 1 ------- 1 =>3*10=30.
So, the total no coin of 5p are 3*10=30.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers