Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 11)
11.
The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
Answer: Option
Explanation:
Let A = 2k, B = 3k and C = 5k.
A's new salary = | 115 | of 2k = | ![]() |
115 | x 2k | ![]() |
= | 23k |
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | ![]() |
110 | x 3k | ![]() |
= | 33k |
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | ![]() |
120 | x 5k | ![]() |
= 6k |
100 | 100 |
![]() |
![]() |
23k | : | 33k | : 6k | ![]() |
= 23 : 33 : 60 |
10 | 10 |
Discussion:
33 comments Page 3 of 4.
Raju kollati said:
9 years ago
110/100 = 1.1.
1.1 * 3 = 3.3.
1.1 * 3 = 3.3.
Koushik datta said:
9 years ago
It can be solve in ay method:
2 * 115 : 3 * 11 : 5 * 120.
= 2 * 23 : 3 * 22 : 5 * 24.
= 23 : 33 : 60.
2 * 115 : 3 * 11 : 5 * 120.
= 2 * 23 : 3 * 22 : 5 * 24.
= 23 : 33 : 60.
(1)
Satham said:
9 years ago
20*115/100 = 23,
30*110/100 = 33,
20*120/100 = 60.
23 : 33 : 60.
30*110/100 = 33,
20*120/100 = 60.
23 : 33 : 60.
(1)
Harshit Anand said:
8 years ago
@Abhinav Kumar.
Why the 10 and x gets cancelled in above question of Ratio and Proportion?
Why the 10 and x gets cancelled in above question of Ratio and Proportion?
Bindhu said:
8 years ago
Can anyone tell me how you can solve 23k/10 : 33k/10 : 6x into 23k : 33k :6k?
Please explain.
Please explain.
Ramu said:
8 years ago
2*1.15, 3*1.1,5*1.2.
2.3, 3.3, 6
23, 33, 60.
2.3, 3.3, 6
23, 33, 60.
(1)
Chandan shil said:
7 years ago
115*2/10=23,
110*3/10=33,
120*5/10=60.
So, 23:33:60.
110*3/10=33,
120*5/10=60.
So, 23:33:60.
(4)
Sardar Bahadar Khan Seehar said:
7 years ago
How 23/10:33/10:6 = 23:33:60?
(3)
Venu said:
7 years ago
115/100*20:110/100*30:120/100*50.
= 23:33:60.
Here 2=20 and 3=30 and 5=50.
= 23:33:60.
Here 2=20 and 3=30 and 5=50.
(2)
Savi said:
7 years ago
Thanks for the answer @Preety.
(3)
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