Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 11)
11.
The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
Answer: Option
Explanation:
Let A = 2k, B = 3k and C = 5k.
A's new salary = | 115 | of 2k = | ![]() |
115 | x 2k | ![]() |
= | 23k |
100 | 100 | 10 |
B's new salary = | 110 | of 3k = | ![]() |
110 | x 3k | ![]() |
= | 33k |
100 | 100 | 10 |
C's new salary = | 120 | of 5k = | ![]() |
120 | x 5k | ![]() |
= 6k |
100 | 100 |
![]() |
![]() |
23k | : | 33k | : 6k | ![]() |
= 23 : 33 : 60 |
10 | 10 |
Discussion:
33 comments Page 1 of 4.
Trimu said:
7 years ago
@All.
A:B:C
2:3:5.
Increments are 15%, 10%, 20% Happen
So we have to find out their new salaries,
A= (2 * 0.15)=0.3 So add this in first ratio.
Then 2+0.3=2.3
Similarly B = (3 * 0.1)=0.3,
B = 3+0.3=3.3,
C =( 5 * 0.2)=1,
C = 5+1,
So the Ratios are now 2.3 : 3.3 : 6,
After multiplying with 100 in each;
= 23:33:60.
A:B:C
2:3:5.
Increments are 15%, 10%, 20% Happen
So we have to find out their new salaries,
A= (2 * 0.15)=0.3 So add this in first ratio.
Then 2+0.3=2.3
Similarly B = (3 * 0.1)=0.3,
B = 3+0.3=3.3,
C =( 5 * 0.2)=1,
C = 5+1,
So the Ratios are now 2.3 : 3.3 : 6,
After multiplying with 100 in each;
= 23:33:60.
(20)
Kalpana Rawat said:
1 year ago
Just let ratio 20:30:50 {easy to calculate}
Calculate increment = 15% of 20 is 3 so the new ratio is 20+3 = 23.
10% of 30 is 3 = 30+3 = 33,
20% of 50 is 10 = 50+10 = 60.
New ratio after increment = 23 : 33 : 60.
Calculate increment = 15% of 20 is 3 so the new ratio is 20+3 = 23.
10% of 30 is 3 = 30+3 = 33,
20% of 50 is 10 = 50+10 = 60.
New ratio after increment = 23 : 33 : 60.
(16)
Krishna pithiya said:
1 year ago
Here, the value of A, B and C is 2:3:5 respectively, and increments are 15%, 10% and 20% so for the new ratio,
(15/100*2 +2) : (10/100*3+3) : (20/100*5+5).
(3+20/10) : (3+30/10) : (5+1).
23/10:33/10:6.
23 :33 : 60.
(15/100*2 +2) : (10/100*3+3) : (20/100*5+5).
(3+20/10) : (3+30/10) : (5+1).
23/10:33/10:6.
23 :33 : 60.
(6)
Chandan shil said:
7 years ago
115*2/10=23,
110*3/10=33,
120*5/10=60.
So, 23:33:60.
110*3/10=33,
120*5/10=60.
So, 23:33:60.
(4)
Savi said:
7 years ago
Thanks for the answer @Preety.
(3)
Sardar Bahadar Khan Seehar said:
7 years ago
How 23/10:33/10:6 = 23:33:60?
(3)
Venu said:
7 years ago
115/100*20:110/100*30:120/100*50.
= 23:33:60.
Here 2=20 and 3=30 and 5=50.
= 23:33:60.
Here 2=20 and 3=30 and 5=50.
(2)
Abhinav Kumar said:
1 decade ago
Let common multiple be x:
A = 15% of 2x+2x.
= 15/100*2x+2x.
= 3/10*x+2x.
= 3x/10+2x = {3x+10(2x)}/10 = 23x/10.
B = 10% of 3x+3x.
= 10/100*3x+3x.
= 3x/10+3x = {3x+10(3x)}/10 = 33x/10.
C = 20% of 5x+5x.
= 20/100*5x+5x.
= 1x/5*5x+5x = 1x+5x = 6x.
A:B:C = 23x/10:33x/10:6x.
= 23x/10:33x/10:6x*10/10 (L.C.M).
= 23x/10:33x/10: 60x/10.
= 23:33:60 (10 and x gets cancelled).
Hope I helped You guys!
A = 15% of 2x+2x.
= 15/100*2x+2x.
= 3/10*x+2x.
= 3x/10+2x = {3x+10(2x)}/10 = 23x/10.
B = 10% of 3x+3x.
= 10/100*3x+3x.
= 3x/10+3x = {3x+10(3x)}/10 = 33x/10.
C = 20% of 5x+5x.
= 20/100*5x+5x.
= 1x/5*5x+5x = 1x+5x = 6x.
A:B:C = 23x/10:33x/10:6x.
= 23x/10:33x/10:6x*10/10 (L.C.M).
= 23x/10:33x/10: 60x/10.
= 23:33:60 (10 and x gets cancelled).
Hope I helped You guys!
(2)
Sourabh said:
1 decade ago
In this example mentioned 15% increase. That happened we are writing 115.
In case here mentioned loss/decrease 15% in this case we are write 85.
In case here mentioned loss/decrease 15% in this case we are write 85.
(1)
Hruaii said:
9 years ago
Why you take 115/100 of 2k instead of 2k+15%? Please explain more in simplest form.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers