Aptitude - Ratio and Proportion - Discussion

Discussion Forum : Ratio and Proportion - General Questions (Q.No. 11)
11.
The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
3 : 3 : 10
10 : 11 : 20
23 : 33 : 60
Cannot be determined
Answer: Option
Explanation:

Let A = 2k, B = 3k and C = 5k.

A's new salary = 115 of 2k = 115 x 2k = 23k
100 100 10

B's new salary = 110 of 3k = 110 x 3k = 33k
100 100 10

C's new salary = 120 of 5k = 120 x 5k = 6k
100 100

New ratio 23k : 33k : 6k = 23 : 33 : 60
10 10

Discussion:
33 comments Page 2 of 4.

Radhika said:   1 decade ago
Preety shortcut is nice.

Rupali Palande said:   1 decade ago
New ratio of their salaries,

115*2=230.

110*3=330.

120*5=600.

i.e 230:330:600.

i.e 23:33:60.

Atul1487 said:   1 decade ago
Simplest way to understand.

15% increment in A Salary, So,
2*15% = 0.3.

Total Salary of A after increment = 2+0.3 = 2.3.

10% increment in B Salary, So,
3*10% = 0.3.

Total Salary of B after increment = 3+0.3 = 3.3.

20% Increment in C Salary, So,
5*20% = 1.

Total Salary of C after increment = 5+1 = 6.

Ratio of salary of A, B & C after increment.

2.3 : 3.3 : 6.0.

So 23 : 33 : 60 Answer.

Narayana Rao Gartam said:   1 decade ago
Let's salaries A,B,C are 200:300:500 i.e 2:3:5.

A-increase of 15% is 200+30 = 230.
B-increase of 10% is 300+33 = 330.

C-increase of 20%b is 500+100 = 600.
Ratio of A:B:C is 230: 330: 600.

i.e 23: 33: 60.

Asma said:   1 decade ago
A man will b three times old in 20 years as he is now. What is his present age?

Narayana Rao Gartam said:   1 decade ago
Hai @Asma, Try below:

Ans, is 10 years.

Say, present age is = X,

After 20 years man age will be 3X = X+20.

i.e, 3X = X+20.

3X-X = 20.

X = 10.

Results, the man present age is 10 years.

Agrima said:   1 decade ago
I still don't understand why we have written 115?

Sourabh said:   1 decade ago
In this example mentioned 15% increase. That happened we are writing 115.

In case here mentioned loss/decrease 15% in this case we are write 85.
(1)

Abhinav Kumar said:   1 decade ago
Let common multiple be x:

A = 15% of 2x+2x.

= 15/100*2x+2x.

= 3/10*x+2x.

= 3x/10+2x = {3x+10(2x)}/10 = 23x/10.

B = 10% of 3x+3x.

= 10/100*3x+3x.

= 3x/10+3x = {3x+10(3x)}/10 = 33x/10.

C = 20% of 5x+5x.

= 20/100*5x+5x.

= 1x/5*5x+5x = 1x+5x = 6x.

A:B:C = 23x/10:33x/10:6x.

= 23x/10:33x/10:6x*10/10 (L.C.M).

= 23x/10:33x/10: 60x/10.

= 23:33:60 (10 and x gets cancelled).

Hope I helped You guys!
(2)

Hruaii said:   10 years ago
Why you take 115/100 of 2k instead of 2k+15%? Please explain more in simplest form.
(1)


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