Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 11)
11.
In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:
Answer: Option
Explanation:
| B runs | 45 | m in 6 sec. |
| 2 |
 B covers 300 m in |
 |
6 x | 2 | x 300 |  sec |
= 80 sec. |
| 45 |
Discussion:
22 comments Page 1 of 3.
Dileeo said:
8 years ago
First of all, everyone having doubt of why 45/2 m/s speed is added to B why not A?
Answer is after race completion B takes that additional 6 sec to complete the race from given data we can find B speed and time
22.5 mts - 6 sec then 300 mts - 80sec it will take to complete 300 mts race here ' -' symbol is equal to.
Answer is after race completion B takes that additional 6 sec to complete the race from given data we can find B speed and time
22.5 mts - 6 sec then 300 mts - 80sec it will take to complete 300 mts race here ' -' symbol is equal to.
Debjani Nandy said:
10 years ago
A has already completed the race when B was 22.5 m behind. Moreover B has taken 6 s more than A to complete the race. So at the time A completes the race, B takes an addition of 6 secs to cover up the distance of 22.5 m by which he was behind. So he travels 22.5 m in the additional 6 sec which is nothing but 45/2 m.
Pankaj said:
1 decade ago
Since A beats B by 22.5 meter (225/10 or 41/2) or 6 sec. It means both quantities are equal.
Or we can say 22.5 m = 6 sec.
Or 22.5 meters covers in 6 sec.
Hence.
1 m = 6/22.5 sec;
So 300 m = (6/22.5)*300 sec;
= 6/(45/2)*300 sec;
= 6*(2/45)*300 sec;
= 80 sec.
Or we can say 22.5 m = 6 sec.
Or 22.5 meters covers in 6 sec.
Hence.
1 m = 6/22.5 sec;
So 300 m = (6/22.5)*300 sec;
= 6/(45/2)*300 sec;
= 6*(2/45)*300 sec;
= 80 sec.
AJAY TOMAR said:
1 decade ago
Let see,
We know "(speed=distance/time)" or S=D/T
Given 22.5m in 6 sec then d=22.5,t=6sec
S=22.5/6
Now we have to find how much time taken to cover 300m distance.
T=D/S
=300/22.5/6
=80s
We know "(speed=distance/time)" or S=D/T
Given 22.5m in 6 sec then d=22.5,t=6sec
S=22.5/6
Now we have to find how much time taken to cover 300m distance.
T=D/S
=300/22.5/6
=80s
Brajesh said:
1 decade ago
See,
(45/2=22. 5).
It is simple that if 22. 5m distance is covered in 6 sec than.
300m distance is covered in (300/ (45/2) ) =300x (2/45) =13.33333 x 6=80 sec.
(45/2=22. 5).
It is simple that if 22. 5m distance is covered in 6 sec than.
300m distance is covered in (300/ (45/2) ) =300x (2/45) =13.33333 x 6=80 sec.
Gopi said:
7 years ago
I agree @Ramya.
80 sec for A to cover 300m since A beats B by 6 sec. 6 sec should add to 80 sec. Therefore 86 sec should be the answer.
80 sec for A to cover 300m since A beats B by 6 sec. 6 sec should add to 80 sec. Therefore 86 sec should be the answer.
(3)
Ramya said:
1 decade ago
80 sec is correct but its only for A to cover 300 m as it beats.
B by 6 sec time taken by B to cover whole 300 m is 80+6 = 86 sec.
B by 6 sec time taken by B to cover whole 300 m is 80+6 = 86 sec.
Keerthika senthur said:
1 year ago
a beats b by 22.5 m. 6 seconds
So A covered 300m before B
So, 300/22.5 = 13.333.
Now 13.333 * 6 = 80.
So A covered 300m before B
So, 300/22.5 = 13.333.
Now 13.333 * 6 = 80.
(1)
VENKATESHBABU said:
7 years ago
Using chain rule:
22.5 ---- 6
300 ---- ?
300/22.5*6 = 80.
If we want A 80-6 = 72.
22.5 ---- 6
300 ---- ?
300/22.5*6 = 80.
If we want A 80-6 = 72.
Vyshu.. said:
9 years ago
Let's the solution is that:-.
6 * (1/22.5) * 300 = 80.
Therefore, 80 sec is the answer.
6 * (1/22.5) * 300 = 80.
Therefore, 80 sec is the answer.
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