Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
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20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
354 comments Page 6 of 36.
Sonam shah said:
4 years ago
25% = 1 ÷ 5 =
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
Vishal Thakur said:
4 years ago
S.P of x Articles = C.P of 20 Articles.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
Rony said:
4 years ago
Cp sp profit=25%(fraction value=1/4)
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
Raghib said:
4 years ago
Let's do it simple way.
Let's assume CP=x and SP=y
First-line says;
20CP=NSP
Let's substitute CP and SP values and we get,
20x=Ny ----- (i) This is our first equation
The second part of the question says;
Profit%=25%.
and we know that Profit%=[(SP-CP) X 100]/CP.
by substituting values we get,
25=[(y-x) X 100]/x.
upon solving we get,
x=(4/5)y ---(ii) this is our equation 2.
by substituting equation (ii) in equation (i) we get,
Ny=20 X (4/5)y.
N=16 -- Hence 16 is our answer.
Let's assume CP=x and SP=y
First-line says;
20CP=NSP
Let's substitute CP and SP values and we get,
20x=Ny ----- (i) This is our first equation
The second part of the question says;
Profit%=25%.
and we know that Profit%=[(SP-CP) X 100]/CP.
by substituting values we get,
25=[(y-x) X 100]/x.
upon solving we get,
x=(4/5)y ---(ii) this is our equation 2.
by substituting equation (ii) in equation (i) we get,
Ny=20 X (4/5)y.
N=16 -- Hence 16 is our answer.
Phani said:
5 years ago
CP of 20 articles= SP of X atricles -->(1).
Let us assume the cost price of each article is 1 rupee.so total cost price for 20 articles is 20 * 1 = 20 rupees.
And the given profit is 25%. So for each we article will get a 25% profit on the cost price
so we will sell each article at 1.25 rupee.
So, now we need to multiply this 1.25 rupee to equal it to 20 rupees(because of given equation (1)) and the number with which we multiply 1.25 is the answer.
1.25*16 = 20.
So, 16 is the answer.
Hope this is clear.
Let us assume the cost price of each article is 1 rupee.so total cost price for 20 articles is 20 * 1 = 20 rupees.
And the given profit is 25%. So for each we article will get a 25% profit on the cost price
so we will sell each article at 1.25 rupee.
So, now we need to multiply this 1.25 rupee to equal it to 20 rupees(because of given equation (1)) and the number with which we multiply 1.25 is the answer.
1.25*16 = 20.
So, 16 is the answer.
Hope this is clear.
PUNYAVATHI said:
5 years ago
From the above question:
20 articles cost price=selling price of x articles so,
20*c.p = s.p*x ----> (1)
s.p=c.p+profit ----> (2).
Given profit=25%=>1/4 on the cost price.
from equation 2.
20*c.p=(c.p+1/4(c.p))x;
20 c.p=5/4 c.p*x,
x = 16,
20 articles cost price=selling price of x articles so,
20*c.p = s.p*x ----> (1)
s.p=c.p+profit ----> (2).
Given profit=25%=>1/4 on the cost price.
from equation 2.
20*c.p=(c.p+1/4(c.p))x;
20 c.p=5/4 c.p*x,
x = 16,
SNR said:
5 years ago
@All.
According to me, the solution is;
CP of 20 articles = SP of x articles.
Profit = 25%.
---> SP = 125% * CP = 1.25 * CP.
---> CP*20 = 1.25*CP*x.
---> 20 = 1.25*x.
---> x = 20/1.25 = 16.
According to me, the solution is;
CP of 20 articles = SP of x articles.
Profit = 25%.
---> SP = 125% * CP = 1.25 * CP.
---> CP*20 = 1.25*CP*x.
---> 20 = 1.25*x.
---> x = 20/1.25 = 16.
Devi said:
5 years ago
Given:
Profit =25%=125%
CP of 20=SP of x
CP*20=SP*X
CP/SP=X/20
CP=20;
SP=X;
In percentage method,
CP = 100% always assume.
100%=x ------>1.
125%=20 ------>2.
Cross multiply or divide the eqn 1 & 2.
Then you will get, x=16.
Profit =25%=125%
CP of 20=SP of x
CP*20=SP*X
CP/SP=X/20
CP=20;
SP=X;
In percentage method,
CP = 100% always assume.
100%=x ------>1.
125%=20 ------>2.
Cross multiply or divide the eqn 1 & 2.
Then you will get, x=16.
Siddhesh Mhatre said:
5 years ago
20*cp = x*sp.
assume cp = 100 and;
sp = profit + cp = 25 + 100 = 125.
Therefore above equation becomes,
20 * 100 = x * 125.
x = 16.
assume cp = 100 and;
sp = profit + cp = 25 + 100 = 125.
Therefore above equation becomes,
20 * 100 = x * 125.
x = 16.
Hrithik said:
5 years ago
Here you can also slove in the following way.
Articales left = 20 - x.
Sold articales = x.
The Profit percentage = (articles left / sold articles) X 100.
25 = (( 20-x )/x) X 100.
And x = 16.
Articales left = 20 - x.
Sold articales = x.
The Profit percentage = (articles left / sold articles) X 100.
25 = (( 20-x )/x) X 100.
And x = 16.
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