Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
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20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 4 of 36.
Arr soubhagya said:
2 years ago
Thanks for your answer @Surbhi Garg.
(3)
VATHSA said:
3 years ago
Why do we have to assume that CP is Rs. 1?
Cant we solve using equations?
Cant we solve using equations?
(2)
Sanjeet kumar said:
1 decade ago
Hi every one
here this problem is a bit difficult to understand. let me give u an another example then we will come to this.
let c.p. of 1 article is Rs. 4 and
let s.p. of 1 article is Rs. 5
now c.p. of 20 article is 20*4=80
and s.p.of 16 article is 16*5=80
the first line of the question said these r equal that is Rs. 80
now come to our problem above.
let c.p of 1 article is Rs.1
here given that c.p. of 20 article is equal to s.p. of x article
so let us calculate c.p. of 20 article=Rs 20
hence s.p. of x article is Rs. 20
so s.p. of 1 article =20/x
profit on one article= (20/x)-1
% profit=((20/x)-1)*100)/1=25
hence x=16
here this problem is a bit difficult to understand. let me give u an another example then we will come to this.
let c.p. of 1 article is Rs. 4 and
let s.p. of 1 article is Rs. 5
now c.p. of 20 article is 20*4=80
and s.p.of 16 article is 16*5=80
the first line of the question said these r equal that is Rs. 80
now come to our problem above.
let c.p of 1 article is Rs.1
here given that c.p. of 20 article is equal to s.p. of x article
so let us calculate c.p. of 20 article=Rs 20
hence s.p. of x article is Rs. 20
so s.p. of 1 article =20/x
profit on one article= (20/x)-1
% profit=((20/x)-1)*100)/1=25
hence x=16
(1)
Bhaskar Gairola said:
1 decade ago
Let C.P. of 1 article =1.
C.P. of x articles = x.
S.P. of x articles = 1.25x.
Given S.P. of x articales = C.P. of 20 articles.
1.25x = 20.
x=16.
C.P. of x articles = x.
S.P. of x articles = 1.25x.
Given S.P. of x articales = C.P. of 20 articles.
1.25x = 20.
x=16.
(1)
Sumit said:
1 decade ago
Let, C.P of 20 articles = S.P of x articles = y.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
So, C.P of 1 article = y/20.
And, S.P of 1 article = y/x.
((y/x-y/20)/(y/20))*100 = 25 ;
[formula: ((S.P-C.P)/C.P)*100 = gain % ].
(20y-xy)/xy = 25/100
(20/x)-1 = 25/100
20/x = 125/100
x = 16.
(1)
Veer M said:
5 years ago
Let the cost price of one article=Rs 100.
profit=25%,
SP =100+25=125,
NOW;
CP of 20 article =SP of X article.
20 * 100 = 125 * X.
X =16.
profit=25%,
SP =100+25=125,
NOW;
CP of 20 article =SP of X article.
20 * 100 = 125 * X.
X =16.
(1)
Somu said:
4 years ago
Cp of 1 article is Rs. 1 so 20 articles cp is Rs. 20.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
Given 25%profit that means on 1 article there is 25% profit so profit is 0.25 on one article then sp of one article is cp + profit = Rs 1.25.
Cp 20 = here we want 20 for how many articles it becomes Rs. 20 @ sp is Rs 1.25 for 4 articles it is 5 so that Rs. 20, 16 articles.
(1)
Komal said:
3 years ago
CP of 20A= S.P OF X ARTICLE.
# SP OF X =20.
So we know S.P of X as well as profit.
SIMPLY APPLY THE FORMULA.
# S.P = (100+ PROFIT %)*CP.
20 = 100* 25/100*C.P.
# C.P = 16.
# ACTUAL VALUE OF X =16.
# SP OF X =20.
So we know S.P of X as well as profit.
SIMPLY APPLY THE FORMULA.
# S.P = (100+ PROFIT %)*CP.
20 = 100* 25/100*C.P.
# C.P = 16.
# ACTUAL VALUE OF X =16.
(1)
Anshuma Chugh said:
2 decades ago
Can you please make me understand by giving more examples?
K soumya said:
2 decades ago
The given solution for the problem is incorrect.
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