IndiaBIX

Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
Profit and Loss
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
15
16
18
25
Answer: Option
Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

20 - x x 100 = 25
x

2000 - 100x = 25x

125x = 2000

x = 16.

Video Explanation: https://youtu.be/sidqvjUoZxY

Discussion:
355 comments Page 23 of 36.
Nat said:   9 years ago
Profit = 25%.
So let c.p = 4 & s.p = 5.
20 * 4 = x * 5 (unknown=x),
16 = x.
Chinni said:   1 decade ago
profit=s.p-c.p
hence cost of 1 article=1
s.p of 1 article=20/x
profit=(20/x)-1
Sarath said:   1 decade ago
Can you explain me about the assumptions it makes me difficult to understand?
Raju said:   1 decade ago
Can you explain me about the assumptions it makes me difficult to understand?
Rohit said:   7 years ago
Why we have to assume and take Rs 1 here?

Can you explain in detail? please.
Shahul Shaji said:   3 years ago
20 CP = x SP.
SP = (20/x) CP,
Profit = 25% = 125/100,
125/100 = 20/x,
x = 16.
(38)
Mallesh goud said:   8 years ago
(a-b) /b*100=gain percentage.

a=20 b=x gain %=25.

If we solve we get x=16.
Stranger said:   2 years ago
How it is? I can't understand, anyone, please explain to me in a simple way.
(21)
JBPATEL said:   9 years ago
(c.p-s.p)/s.p * 100 = per
(20-x)/x * 100 = 25.

Solve it and you get x=16.
VATHSA said:   3 years ago
Why do we have to assume that CP is Rs. 1?

Cant we solve using equations?
(2)
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers