Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
15
16
18
25
Answer: Option
Explanation:

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

20 - x x 100 = 25
x

2000 - 100x = 25x

125x = 2000

x = 16.

Video Explanation: https://youtu.be/sidqvjUoZxY

Discussion:
355 comments Page 16 of 36.

Francis said:   7 years ago
It is given that;

20(C.P)=x(S.P).
And we know that,
Profit=(SP-CP) /CP.
Therefore,0.25=(SP-(SP*x/20))/(SP*x/20)).
Solving the equation we have,
x=16.

Anjali said:   7 years ago
If we have given profit amount and also given a loss amount then how can we calculate the cost price of the product?

Please, anyone, clear my doubt.

Karu said:   6 years ago
Let us assume,

Cost price of 20 articles(cp) = 20 R/s.
Selling price of x articles(sp) = x R/s.

Formula:
(S.P-C.P)/C.P*100=profit;
20-x/x*100 = 25.

Suman Sourav said:   8 years ago
If I bought 20 article and sell 16 article that means 4 article saved, gain 25% (125=20 equ i and 100= x.....Equ 2 ) req article 16 will get easily.

Sai reddy said:   8 years ago
As per given question.

CP of 20 articles =SP of x articles.
CP/SP=X/20.
here CP=x, SP=20.
GAIN%=(GAIN/CP) 100.
25 =(20-X/X)100.
X=16.

Bhaskar Gairola said:   1 decade ago
Let C.P. of 1 article =1.
C.P. of x articles = x.
S.P. of x articles = 1.25x.

Given S.P. of x articales = C.P. of 20 articles.
1.25x = 20.
x=16.
(1)

Shreeshail karajol said:   7 years ago
(20) cp=(x) sp ------> 1.

Profit=25%.

Means
sp = 125% of cp.
sp = 125/100*((x*sp)/20) {because 1}.
1= 125*x/100*20.
2000/125 = x.
X = 16.

Harish said:   6 years ago
20*c.p = x*s.p
Here s.p is 125% of c.p,since there is a profit of 25%.
125% = 5/4,

Therefore,
20*c.p=5/4 (c.p)*x.
c.p get cancelled.
X=16.

Gayathri Ganesan said:   1 decade ago
@Jaya Darshini.

By default if no such values provided for computation in sense we assume such small value as possible that so we assume 1 here.

Utsav said:   8 years ago
@Sanjeet.

"profit on one article= (20/x)-'1'
% profit=((20/x)-'1')*100)/1=25"
Why do we have to subtract 1 in the above two steps?


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