Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
|
![]() |
20 - x | x 100 = 25 | ![]() |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
357 comments Page 15 of 36.
Bharath said:
8 years ago
Just follow the below simple steps.
We assumed that CP of each article is Rs.1 so our SP
Selling Price 20
Profit Percentage 25%
cost Price ?
Well, we all know that SP is inclusive of Profit 25 Percent.Hence in order to calculate the profit, we should calculate as follows 25*125/25 = 4.
Now just deduct your profit from SP.
Which brings up = 16.
We assumed that CP of each article is Rs.1 so our SP
Selling Price 20
Profit Percentage 25%
cost Price ?
Well, we all know that SP is inclusive of Profit 25 Percent.Hence in order to calculate the profit, we should calculate as follows 25*125/25 = 4.
Now just deduct your profit from SP.
Which brings up = 16.
Mamatha said:
8 years ago
Nice explanation guys especially @Jyotsna your formula really works out.
Jyothsna said:
8 years ago
CP 20 = SP x.
CP/SP=x/20.
=>CP =x; SP =20.
Profit=20-x (Profit=SP-CP).
25 = ((20-x)/x)*100 (P%=P/CP*100).
CP/SP=x/20.
=>CP =x; SP =20.
Profit=20-x (Profit=SP-CP).
25 = ((20-x)/x)*100 (P%=P/CP*100).
Jyothsna said:
8 years ago
@Sowmya your explanation is apt without confusing I just wanna to elaborate some of the formulas.
Vibhore said:
8 years ago
@Utsav.
Profit = SP - CP.
Therefore Profit = (20/x) - 1.
And Profit % = (Profit/CP)X100.
Therefore Profit % = (((20/x)-1)/1)X100 = 25 %.
Ans x = 16.
Profit = SP - CP.
Therefore Profit = (20/x) - 1.
And Profit % = (Profit/CP)X100.
Therefore Profit % = (((20/x)-1)/1)X100 = 25 %.
Ans x = 16.
Utsav said:
8 years ago
@Sanjeet.
"profit on one article= (20/x)-'1'
% profit=((20/x)-'1')*100)/1=25"
Why do we have to subtract 1 in the above two steps?
"profit on one article= (20/x)-'1'
% profit=((20/x)-'1')*100)/1=25"
Why do we have to subtract 1 in the above two steps?
Purusottam said:
8 years ago
As far as my calculation is concerned it is 18.75.
Mallesh goud said:
8 years ago
(a-b) /b*100=gain percentage.
a=20 b=x gain %=25.
If we solve we get x=16.
a=20 b=x gain %=25.
If we solve we get x=16.
Basil said:
8 years ago
@Rinku.
Best explanation Really simple. Thank you very much.
Best explanation Really simple. Thank you very much.
Divya Pahwa said:
8 years ago
@Sanjeet Kumar.
Very nice and clear explanation. Thank you.
Very nice and clear explanation. Thank you.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers

