Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
355 comments Page 14 of 36.
Youth said:
1 decade ago
Hey @Kailash I know that you know the answer, but if we do that much lengthy it will take more time. Think about shortcut yaar please. Thank you for giving explanation.
Govin said:
1 decade ago
Profit = SP-CP.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
CP of 20 articles = SP of x articles.
Thus, SP = 20, here assume cost price for this as y.
Profit = 25%.
So, 0.25y = SP-y.
= 0.25y = 20-y.
y = 16.
Vikash said:
4 years ago
What if we take cp of 20 articles = rs 100,
then sp of x articles become =rs 100,
and let cp of x articles be =rs x,
Then,
(100 - x/x) * 100 = 25,
which gives x = 80.
then sp of x articles become =rs 100,
and let cp of x articles be =rs x,
Then,
(100 - x/x) * 100 = 25,
which gives x = 80.
Vishal Thakur said:
4 years ago
S.P of x Articles = C.P of 20 Articles.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
[As C.P of each article is taken as Re. 1].
Therefore, C.P of 20 Articles = Rs. 20.
Therefore, S. P of x Articles = Rs. 20.
Mukul said:
1 decade ago
@priya :- when u got s.p of x article = Rs. 20 and c.p of 1 article is re.1 so for 'x' article c.p will be Rs. x .
now s.p - c.p = profit
hence 20 - x . = profit .
now s.p - c.p = profit
hence 20 - x . = profit .
Sravani said:
7 years ago
CP * 20 articles = SP * x --> (1).
By formula, SP = (100 + profit %) * CP.
=> 125/100 * CP.
substitute in (1),
CP * 20 = 125/100 * CP * x.
x = 2000/125.
x = 16.
By formula, SP = (100 + profit %) * CP.
=> 125/100 * CP.
substitute in (1),
CP * 20 = 125/100 * CP * x.
x = 2000/125.
x = 16.
Roopa said:
1 decade ago
Really nice to join your discussion.
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
I have simple equation;
c.p =s.p
20(Articles) = x(Articles)+profit
it means
1*20=1+.25*x
20=1.25x
20/1.25=x
20*100/125=x
16
AJAY said:
1 year ago
Let c.p(20) = s.p(x) = 100.
c.p(1) = 100/20 = 5
s,p(1) = 100/x.
Formula,
Profit =((s.p-c.p)*100/c.p
25=((100/x)-5)*100/5
By solving this you will get x = 16.
c.p(1) = 100/20 = 5
s,p(1) = 100/x.
Formula,
Profit =((s.p-c.p)*100/c.p
25=((100/x)-5)*100/5
By solving this you will get x = 16.
(21)
Prabhleen Singh said:
9 years ago
Why in this question it is preassumed that C. P of one article is Re.1 and why not Rs.2 or any other value because when we take it to be Rs. 2 it gives x = 32?
Rony said:
5 years ago
Cp sp profit=25%(fraction value=1/4)
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
x :20 means cp=4unit & profit = 1unit.
Then sp=5 unit.
Now 5 unit=20 then 4 unit = 16,
Therefore X = 16.
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