Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
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20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
353 comments Page 13 of 36.
Naveen said:
1 decade ago
C.P of 20 articles = S.P of x articles.
C.P*20 = S.P*x -->eqn 1.
We know that S.P = [(100+gain%)/100]*C.P.
Gain% is given as 25.
Substituting this in eqn 1 we get x = 16.
C.P*20 = S.P*x -->eqn 1.
We know that S.P = [(100+gain%)/100]*C.P.
Gain% is given as 25.
Substituting this in eqn 1 we get x = 16.
Sadee said:
1 decade ago
C.P*20 = S.P*x.
x = C.P*20/S.P.
Gain% = gain/C.P = S.P-C.P/C.P = S.P/C.P-1.
25% = 1/4 = S.P/C.P-1.
C.P/S.P = 4/5.
x = 20*4/5 = 16.
x = C.P*20/S.P.
Gain% = gain/C.P = S.P-C.P/C.P = S.P/C.P-1.
25% = 1/4 = S.P/C.P-1.
C.P/S.P = 4/5.
x = 20*4/5 = 16.
Subrar said:
1 decade ago
Lets cost price of each article be 4.
So cost price of 20 articles = 20*4=80.
So selling price of each article = 4+4*25%= 5.
So selling price of x articles = 5x.
So according to the question 5x = 80.
So x = 80/5= 16.
So cost price of 20 articles = 20*4=80.
So selling price of each article = 4+4*25%= 5.
So selling price of x articles = 5x.
So according to the question 5x = 80.
So x = 80/5= 16.
Kalyanam said:
1 decade ago
Simple it is.
S.P for x articles = C.P (of 20 articles).
Then S.P for 20 articles = ?
S.P = (20/x) *C.P---------- 1.
Profit%= (profit/C.P) *100.
(25/100)*C.P = profit, so profit=C.P/4----------- 2.
But actually formula.
S.P - C.P = profit.
From 1 & 2.
(20/x) *C.P - C.P = C.P/4.
20/x = 5/4.
X= (20/5) *4=16.
I think you understand this simple way of thinking.
Just logic:
In question : profit% has given so S.P>C.P.
So if S.P for xnos is equal to C.P for 20nos.
So S.P for 20nos should be more than S.P for x nos then we will get profit.
So simply S.P for 20 nos > S.P for x nos.
We know already S.P for x nos = C.P.
Then you can find S.P for 20 nos.
That's it.
S.P for x articles = C.P (of 20 articles).
Then S.P for 20 articles = ?
S.P = (20/x) *C.P---------- 1.
Profit%= (profit/C.P) *100.
(25/100)*C.P = profit, so profit=C.P/4----------- 2.
But actually formula.
S.P - C.P = profit.
From 1 & 2.
(20/x) *C.P - C.P = C.P/4.
20/x = 5/4.
X= (20/5) *4=16.
I think you understand this simple way of thinking.
Just logic:
In question : profit% has given so S.P>C.P.
So if S.P for xnos is equal to C.P for 20nos.
So S.P for 20nos should be more than S.P for x nos then we will get profit.
So simply S.P for 20 nos > S.P for x nos.
We know already S.P for x nos = C.P.
Then you can find S.P for 20 nos.
That's it.
Taniya said:
1 decade ago
I wanted to ask why do we take the C.P of x articles? in the Question it is stated that the C.P of 20 articles so we should find the C.P of 20 instead, no?
Noah said:
1 decade ago
Ok lets assume.
Cost price be x and.
Selling price be y.
Since:
(S.P - C.P) / S.P *100 = profit.
Then,
(y - x)/y * 100 = 25/100.
(y - x)/y = 1/4.
When you cross multiply.
4(y - x) = y.
4y - 4x = y.
5y = 4x.
From the question S.P = C.P.
5y = 4*20.
5y/5 = 80/5.
y = 16.
Cost price be x and.
Selling price be y.
Since:
(S.P - C.P) / S.P *100 = profit.
Then,
(y - x)/y * 100 = 25/100.
(y - x)/y = 1/4.
When you cross multiply.
4(y - x) = y.
4y - 4x = y.
5y = 4x.
From the question S.P = C.P.
5y = 4*20.
5y/5 = 80/5.
y = 16.
Johir said:
1 decade ago
Let 20 article price = 20 RS.
.'. Selling price of x article = 20.
25% profit(means cost is 100 then sp 125).
If SP 125 then CP 100.
...... 20 ..... (100/125)*20 = 16.
.'. Selling price of x article = 20.
25% profit(means cost is 100 then sp 125).
If SP 125 then CP 100.
...... 20 ..... (100/125)*20 = 16.
Himanshu said:
1 decade ago
SP = 20.
Gain = 25%.
CP = ?
CP = (100*20)/(100+25).
Gain = 25%.
CP = ?
CP = (100*20)/(100+25).
Pavan divi said:
1 decade ago
Let cost price of an article be "a"
Let selling price of an article be "b"
Cost price of 20 articles is the same as the selling price of x articles. i.e;
20*a = x*b.
Profit = 25%.
((total articles * b) - (total articles * a))/(total articles * a) = 25 /100.
=> (20b-20a)/20a = 1/4.
=> b=5a/4.
Substitute b in 1st equation,
x=16.
Let selling price of an article be "b"
Cost price of 20 articles is the same as the selling price of x articles. i.e;
20*a = x*b.
Profit = 25%.
((total articles * b) - (total articles * a))/(total articles * a) = 25 /100.
=> (20b-20a)/20a = 1/4.
=> b=5a/4.
Substitute b in 1st equation,
x=16.
Geek said:
1 decade ago
It is very simple.
It is given CP of some number of articles is equal to the SP of other number of articles.
Something like this,
CP of 20 apples = SP of 15 apples.
20*CP of each apple= 15*SP of each apple.
20*CP = 15*SP.
NOW just put the formula.
Gain% = CP-SP/CP*100.
It is given CP of some number of articles is equal to the SP of other number of articles.
Something like this,
CP of 20 apples = SP of 15 apples.
20*CP of each apple= 15*SP of each apple.
20*CP = 15*SP.
NOW just put the formula.
Gain% = CP-SP/CP*100.
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