Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 2)
2.
The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
Answer: Option
Explanation:
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
 |
 |
20 - x | x 100 = 25 |  |
| x |
2000 - 100x = 25x
125x = 2000
x = 16.
Video Explanation: https://youtu.be/sidqvjUoZxY
Discussion:
358 comments Page 12 of 36.
SUBHRAJYOTI ROY said:
1 decade ago
PROFIT = 25%.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
SO, FOR 1 ARTICLES. IF C.P = 100 THEN, S.P = 125.
∴ 20*C.P = X*S.P[C.P OF 20 ARTICLES = S.P OF X ARTICLES].
=> 20*100 = X*125.
=> X = (20*100)/125.
=> 16 ANS.
Aksh sharma said:
5 years ago
Cp of 20 articles = SP of x article.
It means cp = x , Sp = 20.
By formula profit % = (sp - cp) 100/cp.
Therefore. Profit % = Profit % ( for comparing),
(20- x)100/x = 25,
By solving x = 16.
It means cp = x , Sp = 20.
By formula profit % = (sp - cp) 100/cp.
Therefore. Profit % = Profit % ( for comparing),
(20- x)100/x = 25,
By solving x = 16.
Sonam shah said:
5 years ago
25% = 1 ÷ 5 =
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
ie,cp = 4
Sp = 5.
1rs = 1article or 20rs sp so
Sp is nt 5.
Now make sp 20,
Sp=5*4,
So cp also 4*4=16,
Now 1article1rs.
Therefore 16articles =16rs.
So no of articles ie x =16.
Hrithik said:
6 years ago
Here you can also slove in the following way.
Articales left = 20 - x.
Sold articales = x.
The Profit percentage = (articles left / sold articles) X 100.
25 = (( 20-x )/x) X 100.
And x = 16.
Articales left = 20 - x.
Sold articales = x.
The Profit percentage = (articles left / sold articles) X 100.
25 = (( 20-x )/x) X 100.
And x = 16.
Swati Pandey said:
8 years ago
Let the CP of 1 article = 100.
By formula, SP = (100 + profit %) * CP.
125/100 * 100 = 125.
CP of 20 articles = 2000.
CP of 20 articles= SP of x articles.
2000= 125 *x.
Therefore, X = 16.
By formula, SP = (100 + profit %) * CP.
125/100 * 100 = 125.
CP of 20 articles = 2000.
CP of 20 articles= SP of x articles.
2000= 125 *x.
Therefore, X = 16.
Avi said:
1 decade ago
simplest method:
Here give 25% profit means 125/100 ok means 5/4 ratio so 20 article.
1st type 4/5*20=16.
2nd type 5/4 do multiply by 4 both because be need 20 article so get 16 sp.
Here give 25% profit means 125/100 ok means 5/4 ratio so 20 article.
1st type 4/5*20=16.
2nd type 5/4 do multiply by 4 both because be need 20 article so get 16 sp.
Milan Viradia said:
7 years ago
Let, CP of 1 article = 1 Rs.
Now, Profit = 25%,
SP of 1 article = 1.25.
Hence, SP of x article = x*1.25.
CP of 20 article = SP of x article.
20 = x * 1.25.
x = 20/1.25.
x = 16.
Now, Profit = 25%,
SP of 1 article = 1.25.
Hence, SP of x article = x*1.25.
CP of 20 article = SP of x article.
20 = x * 1.25.
x = 20/1.25.
x = 16.
Meena said:
1 decade ago
20*c.p=y --->1
s.p*x=y --->2
Cost price of 20 articles is 100%
Then selling price of x articles is 125%
20*100=2000 --->1
125*x=2000 --->2
x=(2000/125)=16
.'. x=16
s.p*x=y --->2
Cost price of 20 articles is 100%
Then selling price of x articles is 125%
20*100=2000 --->1
125*x=2000 --->2
x=(2000/125)=16
.'. x=16
Sourav Gorain said:
1 week ago
CP = 100/article.
SP = 125/article, as we know the profit% is 25%.
Therefore,
CP of 20 articles = SP of x articles.
=> 20 * 100 = x * 125.
=> x = 4 * 4.
=> x = 16 (Ans).
SP = 125/article, as we know the profit% is 25%.
Therefore,
CP of 20 articles = SP of x articles.
=> 20 * 100 = x * 125.
=> x = 4 * 4.
=> x = 16 (Ans).
(4)
Kailash said:
2 decades ago
Profit=x-y/y *100
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
25=20-y/y*100
25/100=20-y/y
1/4=20-y/y
y =4(20-y)
y =80-4y
5y =80
y =80/5
y =16
This is very shortcut method of this types questions.
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