Aptitude - Profit and Loss - Discussion

Given:

CP of 20 articles= SP of X articles.
(they said ''Let CP be 1 foe each article'').
For better understanding let be do it with the next number.

Let the CP be 2.

CP fox X articles = 2X.

CP of 20 articles= SP of X articles(given).
2 x 20 = SP for X articles.

Profit= SP - CP.
= 40-2X.

Profit %= Profit x 100/CP.
25 = 40-2X x 100/2X
25 = 20-X x 100/X
X = 20-X x 100/25
X = (20-X) x 4.
X = 80- 4X.
X + 4X = 80.
5X = 80,
X= 16.

CP*20 = SP*X.
CP/SP = X/20.
100/125 = X/20(profit is 25%, therefore if we take CP as 100% then SP will b 125%).
X = 16.

25 is the answer.

Cost price 20(1+25%100).
20*125%100 = 25.

Profit = 25%.

%profit= ((sp-cp) /cp)) * 100.
cp = x.
sp = 20.
25 = (20-x / x)*100.
x = 20 * 4-4x.
3x = 80.
x = 16.

Thanks for the explanation @Sanjeeth.

Thanks for your answer @Habib.

1.25x = 20,
x = 16.

If we have given profit amount and also given a loss amount then how can we calculate the cost price of the product?

Please, anyone, clear my doubt.

If 20 article=100rs then each article=100/20=5.
X article= 100rs then each article=100/X,
Formula- %profit={(SP-CP)/CP}*100.
25={(100/X-5)/5}*100,
25={(100-5X/X)/5}*100,
25={(100-5X)/5X}*100,
25/100={(100-5X)/5X},
(1/4) 5X=(100-5X),
5X = 400-20X,
5X+20X = 400,
25X = 400,
X = 400/25=16.

Profit 25% = 125#
125 - 20
100 - ?.
100 * 20/125 = 16.