Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 14)
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
5 15 % loss
17
5 15 % gain
17
6 2 % gain
3
None of these
Answer: Option
Explanation:

C.P. of 1st transistor = Rs. 100 x 840 = Rs. 700.
120

C.P. of 2nd transistor = Rs. 100 x 960 = Rs. 1000
96

So, total C.P. = Rs. (700 + 1000) = Rs. 1700.

Total S.P. = Rs. (840 + 960) = Rs. 1800.

Gain % = 100 x 100 % = 5 15 %
1700 17

Discussion:
41 comments Page 2 of 5.

Felix said:   9 years ago
@Priya,

Let we assume 100 if the base cost price is not given.

BALU said:   10 years ago
Cp of trans1 = 100*840/120 = 700.

Cp of trans2 = 100*960/96 = 1000.

Gain = 400*100/1700 = 400/17.

Dinesh said:   9 years ago
Can we solve this using alligation?

Satish said:   8 years ago
How can 5.88 can be converted to 5 * 15/17?

Cathy said:   8 years ago
How can we say here loss is incurred?

Shinjinee Ghatak said:   8 years ago
What is the gain% formula? Please tell me.

Surya said:   8 years ago
c.p. = s.p/profict%+c.p.%

Easy method find cost price.
C.P. % = 100 %.
So, 840/100+20 = 840/120 = 700.

Faklandu said:   7 years ago
Why not A? Here it is asking both gain or loss right?

Rakesh said:   7 years ago
How CP can be calculated easily? Can anyone give me the shortcut?

Sidharth singhaniya said:   7 years ago
Can Anyone solve it by Easy Ratio Method ?


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