Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 14)
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
Answer: Option
Explanation:
C.P. of 1st transistor = Rs. | ![]() |
100 | x 840 | ![]() |
= Rs. 700. |
120 |
C.P. of 2nd transistor = Rs. | ![]() |
100 | x 960 | ![]() |
= Rs. 1000 |
96 |
So, total C.P. = Rs. (700 + 1000) = Rs. 1700.
Total S.P. = Rs. (840 + 960) = Rs. 1800.
![]() |
![]() |
100 | x 100 | ![]() |
= 5 | 15 | % |
1700 | 17 |
Discussion:
41 comments Page 2 of 5.
Felix said:
9 years ago
@Priya,
Let we assume 100 if the base cost price is not given.
Let we assume 100 if the base cost price is not given.
BALU said:
10 years ago
Cp of trans1 = 100*840/120 = 700.
Cp of trans2 = 100*960/96 = 1000.
Gain = 400*100/1700 = 400/17.
Cp of trans2 = 100*960/96 = 1000.
Gain = 400*100/1700 = 400/17.
Dinesh said:
9 years ago
Can we solve this using alligation?
Satish said:
8 years ago
How can 5.88 can be converted to 5 * 15/17?
Cathy said:
8 years ago
How can we say here loss is incurred?
Shinjinee Ghatak said:
8 years ago
What is the gain% formula? Please tell me.
Surya said:
8 years ago
c.p. = s.p/profict%+c.p.%
Easy method find cost price.
C.P. % = 100 %.
So, 840/100+20 = 840/120 = 700.
Easy method find cost price.
C.P. % = 100 %.
So, 840/100+20 = 840/120 = 700.
Faklandu said:
7 years ago
Why not A? Here it is asking both gain or loss right?
Rakesh said:
7 years ago
How CP can be calculated easily? Can anyone give me the shortcut?
Sidharth singhaniya said:
7 years ago
Can Anyone solve it by Easy Ratio Method ?
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