Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 1)
1.
Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is:
Answer: Option
Explanation:
Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.
Selling Price (S.P.) = Rs. 5800.
Gain = (S.P.) - (C.P.) = Rs.(5800 - 5500) = Rs. 300.
| Gain % = |  |
300 | x 100 |  % |
= 5 | 5 | % |
| 5500 | 11 |
Discussion:
145 comments Page 13 of 15.
Murthyalex said:
1 decade ago
The difference between 58% of a number and 39% of the same number is 247. What is 62% of that number?
Pranav Rastogi said:
1 decade ago
Total cost= 4800+700=5500
and selling price= 5800
so profit= 300
and profit% = 300/5500*100 = 5(5/11)
and selling price= 5800
so profit= 300
and profit% = 300/5500*100 = 5(5/11)
Malathy said:
1 decade ago
Thanks rahul nice explanation.
Munna said:
1 decade ago
It is simplification process.
[(11*5)+5]/11=60/11.
[(11*5)+5]/11=60/11.
RAHUL said:
1 decade ago
How did 5.5/11 come?
ANS: Gain% = (300 x 100)/5500
= 30000/5500
= 300/55
= 60/11
NOW dont calculate ans in decimal instead get ans. in the form of quotient remainder and divisor
Here QUOTIENT=5
REMAINDER=5
DIVISOR=11
SO V GET 5(5/11)
ANS: Gain% = (300 x 100)/5500
= 30000/5500
= 300/55
= 60/11
NOW dont calculate ans in decimal instead get ans. in the form of quotient remainder and divisor
Here QUOTIENT=5
REMAINDER=5
DIVISOR=11
SO V GET 5(5/11)
Kalpana said:
1 decade ago
@ sam
900%
S.P-C.P= Gain
Gain %= Gain/C.P*100
900%
S.P-C.P= Gain
Gain %= Gain/C.P*100
Swapnil said:
1 decade ago
Which one is correct? either 25% or 50%? we have to calculate profit on cost price, isn't it?
Priya said:
1 decade ago
If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain? Please solve this.
Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins. If 3/4th of the tank is filled by Pipe B alone and both are opened, how much time is required by both the pipes to fill the tank completely.
Pipe A can fill a tank in 30 mins and Pipe B can fill it in 28 mins. If 3/4th of the tank is filled by Pipe B alone and both are opened, how much time is required by both the pipes to fill the tank completely.
Sunil said:
1 decade ago
Sam buys an old pen for Rs. 10 and If he sells for Rs. 100, his gain percent is:
Kiruthi said:
1 decade ago
I need to know how the ans 5.454545 can be write in fraction as 5(5/11) %. Give a solution for me.
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