Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option
Explanation:
Let the speed of the second train be x km/hr.
| Relative speed | = (x + 50) km/hr | |||||||
|
||||||||
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![]](/_files/images/aptitude/1-sym-cbracket-h1.gif)
Distance covered = (108 + 112) = 220 m.
 |
220 | = 6 | ||
|
250 + 5x = 660
x = 82 km/hr.
Discussion:
77 comments Page 6 of 8.
Sriram said:
8 years ago
We have got v (kmph) if it had been v * 5/18 then we would have gotten speed in m/s.
Amitesh said:
9 years ago
220/6 = 250 + 5x/18,
By solving it we get,
3960 = 1500 + 30x,
2460 = 3x,
So, x = 82.
By solving it we get,
3960 = 1500 + 30x,
2460 = 3x,
So, x = 82.
Rocky said:
1 decade ago
I would like to bring this error to your notice that it is 82 m/s and not 82 km/hr.
Gargi Banerjee said:
1 decade ago
Please give an appropriate answer with perticular reason, this is not clear to me.
Karthika said:
1 decade ago
Hey the final answer is in m/s its not in km/h can some one clarify my doubt.
Kajal said:
5 years ago
Why have we assumed x in km/he why not in m/s?
Please, someone, explain it.
Please, someone, explain it.
Student said:
1 decade ago
Well I have a doubt, how did you get 5/18? Sorry if it is a stupid question!
Nagesh said:
3 years ago
6 = 220 then,
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
36 = (x+50)*10.
After cross multiple;
6*22 = X + 50.
X = 82.
Shree said:
1 decade ago
(108+112)/6 = 50 + x.
(220/6)*(18/5) = 50 + x.
132 = 50 + x.
x = 82 Km/hr.
(220/6)*(18/5) = 50 + x.
132 = 50 + x.
x = 82 Km/hr.
Moin said:
9 years ago
But can't do in direct formula of a + b/u + v = t? Then finding us there.
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